C Bytes with spices of Linux & Opensource

Encrypt a 4 digit number by adding 7 to each digit and swapping first with third & 2nd with 4rth digit & Decrypt to original again

noreply@blogger.com (Anonymous) — Mon, 08 Jul 2013 15:57:00 +0000

Encrypt a 4 digit number in such a way that ,later on Decrypt the number to original number :

1)Your program should read a four-digit integer in such a way that it replaces each digit by(sum of that digit + 7)
2)Swap 2nd digit with 4rth
3)Swap 1st digit with 3rd
4)Print the encrypted number



#include <stdio.h>

int main(void)

{

    int num,dig,mod,total = 0,div = 1000,base = 1000,dig1,dig2,dig3,dig4;

    printf("Enter a 4 digit +ve number to be Encrypted : ");

    scanf("%d",&num);

  

    if ( num > 999 && num <= 9999)

    {

        while ( num != 0)

        {

            dig = num / div + 7;

            total = total * 10 + dig ;

            num = num % base;

            div = div / 10;

            base = base / 10;

          

        }

        printf("Total encrypted number is %d",total);

      

            dig1 = (total/1000);

            dig2 = (total % 1000 / 100);

            dig3 = (total % 100 / 10);

            dig4 = (total % 10);

            printf("\nNew Encrypted number is %d%d%d%d",dig3,dig4,dig1,dig2);

    }

    else

        printf("Please Enter a 4 digit +ve number : ");

  

  

    return 0;

}

Part 2 : Decryption to original number :



#include <stdio.h>

int main(void)

{

    int num,dig1,dig2,dig3,dig4,base = 1000,div = 1000,mod,total = 0;

    printf("\nEnter an Encrypted four digit number : ");

    scanf("%d",&num);



    if ( num > 999 && num <= 9999)

    {

        

        dig1 = num / base ;

        dig2 = (num % base)/100 ;

        dig3 = (num % 100)/10 ;

        dig4 = (num % 10);



        num = dig3*1000+dig4*100+dig1*10+dig2;



        while( num != 0)

        {

            mod = num / base - 7;

            total = total + mod * base;

            base = base / 10;

            num = num % div;

            div = div / 10;

        }

        printf("\nDecrypted number is %d",total);

    }

    else

        printf("\nPlease enter a +ve 4 digit number & try again ");

    return 0;

    



}

Convert a Decimal number into Binary number

noreply@blogger.com (Anonymous) — Thu, 04 Jul 2013 12:30:00 +0000


#include <stdio.h>

int main(void)

{

    int number,mod,base = 1,total = 0 ;



    printf("\nEnter a decimal number and I'll let you know Binary of it : ");

    scanf("%d",&number);



    while ( number != 0)

    {

       mod = number % 2 ;

       total = total + mod * base ;

       number = number/2;

       base = base * 10;

    }

  

    printf("\nBinary number of decimal %d is %d",number,total);



    return 0;

}

Convert a Binary number to Decimal number without using Pow() or Arrays or Functions

noreply@blogger.com (Anonymous) — Wed, 03 Jul 2013 10:48:00 +0000


#include <stdio.h>

int main(void)

{

    long int bin;

    int total = 0 ,dec,mod,base =1 ;



    printf("\nEnter a binary number(0's & 1's),I'll tell you its decimal : ");

    scanf("%ld",&bin);



    while ( bin != 0  )

    {

        mod = bin % 10;

        total = total + base * mod;

        base = base * 2 ;

        bin =  bin / 10;

    }



    printf("\nDecimal of %ld is %d",bin,total);

    return 0;

}

Enter a 5 digit number to see if its Palindrome number :- For Eg : 12321,45554, 11611

noreply@blogger.com (Anonymous) — Tue, 02 Jul 2013 17:37:00 +0000

#include <stdio.h>
int main(void)
{
int i,mod,total,temp;
printf("\nEnter a +ve 5 digit number : ");
scanf("%d",&i);
temp = i;

if ( i > 9999 && i <= 99999 )
{
while ( i != 0)
{
mod = i % 10;
total = total * 10 + mod ;
i = i / 10;
}

if (total == temp)
printf("%i is Palindrome ",temp);
else
printf("%i is not Palindrome",temp);
}
else
printf("Pl. Enter a +ve 5 digit number :");

return 0;
}

Print an asterisks( * ) Square out of side size's number input

noreply@blogger.com (Anonymous) — Sun, 30 Jun 2013 06:17:00 +0000

Write a Program that reads in the side of a square and then prints that square out of asterisks.Your program should work for squares of all sides sizes between 1-20.For example it should look like this :

*****
* *
* *
* *
*****

Code :

#include <stdio.h>
int main(void)
{
int i = 1,sides,j = 1,m = 1,b = 1,n;
printf("Enter number of sides of square to be printed :");
scanf("%d",&sides);
while ( m <= sides)
{
printf("*");
m++;
}

while ( b < sides - 1)
{
printf("\n*");
n = 2;
while ( n < sides )
{
printf(" ");
n++ ;
}
if ( n == sides)
printf("*");
b++;
}
printf("\n") ;
while ( i <= sides)
{
printf("*");
i++;
}
return 0;
}

21 Matchstick Game in C

noreply@blogger.com (Anonymous) — Thu, 02 Aug 2012 14:35:00 +0000

21 Matchstick Game using C Programming

Write a program for a matchstick game being played between the computer and a user.
Your program should ensure that the computer always wins. Rules for the game are as follows:

-There are 21 matchsticks.
-The computer asks the player to pick 1, 2, 3 or 4 matchsticks.
-After the person picks, the computer does its picking.
-Whoever is forced to pick up the last matchstick loses the game.

Code :

=======

#include <stdio.h>

int main(void)

{

int i,total = 0,choice,matches = 21,left = 0,k = 0;

while ( total < 20 )

{

printf("\nEnter your choice of match-sticks between 1-4 :");

scanf("%d",&i);

if ( i > 4 || i <= 0 )

{

printf("Pl.Enter a valid no between 1,2,3 or 4 :");

continue;

}

total = total + i ;

left = left - total ;

if( total >= 21)

break;

choice = 5 - i ;

printf("\nComputer chooses %d",choice);

total = total+choice ;

left = left - choice ;

printf("\n \nNow total match sticks are %d",total);

if (total == 20)

{

while (k != 1)

{

printf("\nEnter your choice of M-sticks you have just one left :");

scanf("%d",&k);

if ( k != 1)

printf("\nPl.enter valid choice : 1 ");

continue;

}

if(k == 1)

{

total = total + k;

printf("\nComputer wins as you are last to choose match-stick");

printf("\n \nNow total match sticks are %d",total);

}

return 0;

}

Find Binary Number Of Any Given Decimal Number

noreply@blogger.com (Anonymous) — Fri, 09 Sep 2011 06:15:00 +0000

/*Find Binary Number Of Any Given Decimal Number (In Reverse Order) */

#include <stdio.h>
int main(void)
{
int num,j,k = 0;
printf("Enter a number whose binary you want to know :");
scanf("%d",&num);
j = num ;

while ( j > 0)
{
k = j % 2;
printf("%d ",k );
j = j / 2 ;
continue;
}

printf("\n");
return 0;

}

Euclid's Geometric Position

noreply@blogger.com (Anonymous) — Fri, 09 Sep 2011 06:11:00 +0000

/*According to Euclid's Geometric Position find Integer Factorization/Prime Factorization of Given Number */

#include <stdio.h>

int main(void)
{
int i,num,j;
printf("Enter a number whose Prime factors you want to find :");
scanf("%d",&num);
j = num ; //Assigning value of num to j

for ( i = 2 ; i <= j-1 ;i++)
{
while( num % i == 0)
{
printf("\n%d ",i );
num = num / i ;
continue;
}

}

printf("\n");
return 0;

}

According to the Gregorian calendar,it was Monday on the date 01/01/1900.If any year is input through the keyboard write a program to find out what is the day on 1st January of this year

noreply@blogger.com (Binita M Shah) — Mon, 05 Sep 2011 11:23:00 +0000

Solution code:-
=========

Easy One (Irrespective of difference between year input from year 1901) :

/*According to the Gregorian calender, it was Monday on the date 01/01/01. If any year is input
* through the keyboard write a program to find out what is the day on 1st January of this year?*/

#include <stdio.h>
int main(void)
{
int yr,diff,lpyrdays,normaldays,res;
printf("\nEnter a year whose day of 1st Jan you want to know : ");
scanf("%d",&yr);

yr = (yr - 1) ; //removing 1 year as only 1 day we are calculating of current yr
lpyrdays = (yr/4) + (yr / 400) - (yr / 100 ); //Calculating leap days in that particular year
normaldays = (yr* 365 )+ 1 + lpyrdays ; //Calculating normal days in that year & adding 1st jan's 1 day in
res = normaldays % 7;

if(res==0)
printf("\nSunday");
if(res==1)
printf("Monday");
if(res==2)
printf("Tuesday");
if(res==3)
printf("Wednesday");
if(res==4)
printf("Thursday");
if(res==5)
printf("Friday");
if(res==6)
printf("Saturday");

return 0;

}

Tough One (Solution Code):

#include <stdio.h>

int main(void)          //main function.. starting of c code
{
    int year,differ,lp_year,day_type;
    long int days;


    printf("Please enter the year: ");
    scanf("%d",&year);
    year=year-1; //we will find days before given year so
    differ=year-1900;

   /*as leap year is not divisible by 100.so,create 2 condition
   one difference less than 100 and greater than 100*/

   if(differ<100)
   {
   lp_year=differ/4; //caln of total no. of leap year
   days=(366*lp_year)+((differ-lp_year)*365+365+1);//see Note1
   day_type=days%7; //caln of day type sun, mon......
   }

   if(differ>=100)
   {
   lp_year=(differ/4)-(differ/100)+1+((year-2000)/400);//see Note2
   days=(366*lp_year)+((differ-lp_year)*365+365+1);//see Note3
   day_type=days%7;
   }

if(day_type==0)
printf("\nSunday");
if(day_type==1)
printf("Monday");
if(day_type==2)
printf("Tuesday");
if(day_type==3)
printf("Wednesday");
if(day_type==4)
printf("Thursday");
if(day_type==5)
printf("Friday");
if(day_type==6)
printf("Saturday");




    return 0; //int main() is function so value must be return.
               //u will read in function chapter
}

/*Note1:
-leap year has 366 day so lp_year*366
-remaining year has 365 day so (differ-lp_year)*365
-add 365 because we reduce 1 year
-add 1 to make jan 1 on which we find day type

Note2:
-(leap year come in every 4 year so) (differ/4) for leap year
-(leap year isn't divisible by 100 so we subtract (differ/100)
from counting as leap year
-(leap year will be if divisible by 400 so ((year-2000)/400)
to count that year as leap year
- we calculate from 2000 so we add 1

Note3:
-leap year has 366 day so lp_year*366
-remaining year has 365 day so (differ-lp_year)*365
-add 365 because we reduce 1 year
-add 1 to make jan 1 on which we find day type */

Validate if given number is Palindrome or not

noreply@blogger.com (Binita M Shah) — Wed, 24 Aug 2011 12:58:00 +0000

#include <stdio.h>

int main(void)

{

int i,num,rev= 0,j = 0;

printf("Enter a number for Palindrome check :");

scanf("%d",&i);

num = i;

while ( i != 0 )

{

rev = i % 10;

j = rev + j * 10 ;

i = i / 10 ;

}

if ( j == num)

printf("\n %d is palindrome",num);

else

printf("\n %d is not Palindrome\n",num);

return 0;

}

Find Prime Factorization of given number

noreply@blogger.com (Binita M Shah) — Sun, 08 May 2011 13:20:00 +0000

/*Find Prime Factorization Of Any Given Number */

#include <stdio.h>
int main(void)
{
int i,num,j,k;
printf("Enter an integer whose Prime factors you want :");
scanf("%d",&num);
k = num ;
for(i = 2 ; i <= num ; i++)
{
for (j = 2 ; j <= i - 1 ; j++)
{
if ( i % j == 0)
break;
}
if (i == j)
{
while ( k % i == 0)
{
printf("%d ",i);
k = k / i ;
continue;

}

}

}
return 0;
}

Bifurcate entered sentence into uppercase,lowercase,number,special characters & count at the end

noreply@blogger.com (Binita M Shah) — Sun, 21 Mar 2010 12:45:00 +0000

/*End user enters sentence/s and you need to bifurcate each entered character whether its number,uppercase character,lower case character ,special character,whitespace character,tab/new line and then reprint the same sentence/s on new line*/

#include <stdio.h>

int main(void)

{

int i;

int big = 0,num = 0,sp = 0,small = 0,space = 0;

while ( (i = getchar()) != EOF )

{

if (( i >= 'a') && ( i <= 'z'))

small++;

else if (( i >= 'A') && ( i <= 'Z'))

big++;

else if (( i >= '0') && (i <= '9'))

num++;

else if ((( i >= 0) && (i <= 31)) || (( i >= 33) && ( i <= 47)) ||((i >= 58) && (i <= 64)) || (( i >= 91) && ( i <= 96)) || (( i >= 123) && ( i <= 127))) //special characters

sp++;

else if (( i == 32) || ( i == 9) || ( i = 10) || ( i = 13)) // for space,tab,newline

space++;

putchar(i);

}

printf("%d lower characters are entered \n",small);

printf("%d Uppercase characters are entered \n",big);

printf("%d White space characters are entered \n",space);

printf("%d Numerical characters are entered \n",num);

printf("%d Special characters are entered \n",sp);

return 0;

}

Freenode IRC - Connect via Openssl with SASL authentication

noreply@blogger.com (Binita M Shah) — Mon, 22 Feb 2010 12:10:00 +0000


Migration of freenode to new server from hyperion-ircd to ircd-seven happened in January end,2010.With which one can connect to IRC freenode via OpenSSL encryption between client & server .Using a script in Irssi one can get authentication via SASL.Freenode's standard port is 6667 but listen's for SSL connections on ports 7000 and 7070.So here are steps of how to get SSL and SASL setup for Irssi:

1)Perl libraries required: Before hand to run Irssi script pre-requisite perl lib are Blowfish, DH and BIGNUM

2)For Debian/Ubuntu ( install irssi,perl lib pre-requisites & Openssl) :

sudo apt-get install irssi openssl libcrypt-openssl-bignum-perl libcrypt-dh-perl libcrypt-blowfish-perl

3)At terminal:

cd ~/.irssi/scripts
sudo mkdir autorun  ## only if you do not have this directory already
sudo wget http://www.freenode.net/sasl/cap_sasl.pl  ##location of cap_sasl.pl is ~/.irssi/scripts/autorun/
cd autorun
sudo ln -s ../cap_sasl.pl cap_sasl.pl

4)Start up irssi without connecting to anything :

irssi -!

5)Once in Irssi,at Status, setup your username and password for SASL:
  /server add -auto -ssl -network freenode irc.freenode.net 7000
  /server add -auto -ssl -ssl_cacert /etc/ssl/certs/GandiStandardSSLCA.pem -network freenode irc.freenode.net 7000(##Incase if you have any certification issues pass these command)  
  /sasl set freenode your_nick your_password DH-BLOWFISH
  /sasl save
  /save
    
6)Quit Irssi

7)Edit config file of irssi :

sudo vi ~/.irssi/config (## search for section servers and see if below entries matches & update as below)

  address = "chat.us.freenode.net";
  chatnet = "freenode";
  port = "7000";
  use_ssl = "yes";
  ssl_verify = "yes";
  ssl_capath = "/etc/ssl/certs";
  autoconnect = "yes";

8)Now simply fire up irssi-windows ( for window's navigation btw channels).You may get something like these :

17:36 -!- Irssi: Looking up chat.us.freenode.net
17:36 -!- Irssi: SASL: auth loaded from /home/binnishah/.irssi/sasl.auth
17:36 -!- Irssi: Connecting to chat.us.freenode.net [140.211.166.4] port 7000
17:36 -!- Irssi: Connection to chat.us.freenode.net established
17:36 !niven.freenode.net *** Looking up your hostname...
17:36 !niven.freenode.net *** Checking Ident
17:36 -!- Irssi: CLICAP: supported by server: identify-msg multi-prefix sasl
17:36 -!- Irssi: CLICAP: requesting: multi-prefix sasl
17:36 -!- Irssi: CLICAP: now enabled: multi-prefix sasl
17:36 -!- binnishah!binnishah@unaffiliated/abms1116 abms1116 You are now logged in as abms1116.
17:36 -!- Irssi: SASL authentication successful
17:36 -!- Welcome to the freenode Internet Relay Chat Network binnishah
17:36 -!- Your host is niven.freenode.net[140.211.166.4/7000], running version ircd-seven-1.0.1
17:36 -!- This server was created Sat Jan 30 2010 at 21:09:36 UTC
17:36 -!- niven.freenode.net ircd-seven-1.0.1 DOQRSZaghilopswz CFILMPQbcefgijklmnopqrstvz bkloveqjfI
17:36 -!- CHANTYPES=# EXCEPTS INVEX CHANMODES=eIbq,k,flj,CFLMPQScgimnprstz CHANLIMIT=#:120 PREFIX=(ov)@+ MAXLIST=bqeI:100 MODES=4 NETWORK=freenode KNOCK STATUSMSG=@+ CALLERID=g are supported by this server
17:36 -!- SAFELIST ELIST=U CASEMAPPING=rfc1459 CHARSET=ascii NICKLEN=16 CHANNELLEN=50 TOPICLEN=390 ETRACE CPRIVMSG CNOTICE DEAF=D MONITOR=100 are supported by this server
17:36 -!- FNC TARGMAX=NAMES:1,LIST:1,KICK:1,WHOIS:1,PRIVMSG:4,NOTICE:4,ACCEPT:,MONITOR: EXTBAN=$,arx WHOX CLIENTVER=3.0 are supported by this server
17:36 -!- There are 899 users and 52716 invisible on 23 servers
17:36 -!- 37 IRC Operators online
17:36 -!- 58 unknown connection(s)
17:36 -!- 27761 channels formed
17:36 -!- I have 2559 clients and 1 servers
17:36 -!- 2559 4459 Current local users 2559, max 4459
17:36 -!- 53615 60092 Current global users 53615, max 60092
17:36 -!- Highest connection count: 4460 (4459 clients) (271988 connections received)
17:36 -!- - niven.freenode.net Message of the Day



*Xchat configuration to SSL :

From Menu select--> Network list -->Networks -->Select freenode --> Edit-->Servers for freenode -->Add "irc.freenode.net/7070" -->set nickserv password
On same window you may find --> Connecting -->Click on "Use SSL for all servers on these Network"

On connection via SSL with port 7070 on Xchat ,you may find it like these:

* * Certification info:
*   Subject:
*     OU=Domain Control Validated
*     OU=Gandi Standard Wildcard SSL
*     CN=*.freenode.net
*   Issuer:
*     C=FR
*     O=GANDI SAS
*     CN=Gandi Standard SSL CA
*   Public key algorithm: rsaEncryption (2048 bits)
*   Sign algorithm sha1WithRSAEncryption
*   Valid since Jan 13 00:00:00 2010 GMT to Jan 13 23:59:59 2011 GMT
* * Cipher info:
*   Version: TLSv1/SSLv3, cipher DHE-RSA-AES256-SHA (256 bits)
* Connected. Now logging in...
* *** Looking up your hostname...
* *** Checking Ident
* Welcome to the freenode Internet Relay Chat Network abms1116
* Your host is barjavel.freenode.net[78.40.125.4/7070], running version ircd-seven-1.0.0


Public Key   : 12695C6D
Fingerprint : 0131 E273 B314 E8C8 2599  E32D 99AA 9362 1269 5C6D

How to enable TATA Photon whiz on Ubuntu 9.04/Fedora 11

noreply@blogger.com (Binita M Shah) — Mon, 26 Oct 2009 14:34:00 +0000

For all those who are using TATA Photon whiz (Hauwei -EC121 or others) these is small - "How to for Ubuntu 9.04 Jaunty Jackalope & Fedora 11" ,which by default can't Plug n play (atleast for me on Ubuntu :))even with Network Manager Applet -->Mobile broadband --> Country = India --> Provider -->Tata indicom ( Plug2Surf) -->Uname: internet,Password=internet,Ph =#777 ( As its CDMA).

# Ubuntu 9.04 Photon Whiz set up

1)By default Ubuntu 9.04 doesn't have wvdial ,so you can install it via #Synaptic Package Manager -->search for wvdial

---OR--
Insert original Ubuntu Cd

Go to System->Administration->software sources. add cd as a source and close . It will update itself, Then on terminal type,

sudo apt-get install wvdial .

2) Type lsusb command and see what it gives (for me below was result)

binnishah@google:~$ lsusb
Bus 001 Device 001: ID 1d6b:0002 Linux Foundation 2.0 root hub
Bus 005 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub
Bus 004 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub
Bus 003 Device 002: ID 045e:00a4 Microsoft Corp.
Bus 003 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub
Bus 002 Device 005: ID 12d1:1411 Huawei Technologies Co., Ltd. ---------> ( Model #,vendor# & product# to trace for modprobe just in case your OS can't catch it plug n play)
Bus 002 Device 001: ID 1d6b:0001 Linux Foundation 1.1 root hub

3)I have Huawei Mobile connect whose model # is EC121 and vendor = 12d1 & product=1411
next,

modprobe usbserial vendor=0xAAAA product=0xBBBB ,

Where AAAA is 12d1 and BBBB is 1411 in my case.

4)Open terminal and give command ( pl.give these while inserting USB photon drive in lap/Server)

sudo wvdialconf /etc/wvdial.conf ---> (These will detect the modem and install it for internet connection by inserting appropriate modem configuration into /etc/wvdial.conf)

** Pl.dont forget sudo or else you will be trapped into permission issues of /usr/sbin/pppd & chap-secrets & pap-secrets permissions and worse would be wvdial.conf wont get Baud speed rate self detected ,neither exact location of modem would be traced

5) Open wvdial.conf in /etc with :-

sudo vi /etc/wvdial.conf ,it has some entries by default add some new & match it as belows:

[Dialer Defaults]
Init1 = ATZ
Init2 = ATQ0 V1 E1 S0=0 &C1 &D2 +FCLASS=0
Init3 = AT+CRM=1
Stupid Mode = 1
New PPPD = Yes
Modem Type = USB Modem
Phone = #777
ISDN = 0
Password = internet ---> Your ph number of tata/password
Username = internet --> Your uname /#
Modem = /dev/ttyUSB0
Baud = 9600 -->Baud rate would be decided by 4rth command and written automatically into wvdial.conf script

Now save & exit vi,

6)type sudo wvdial

It may give you something like these:--

binnishah@google:~$ sudo wvdial
--> WvDial: Internet dialer version 1.60
--> Cannot get information for serial port.
--> Initializing modem.
--> Sending: ATZ
ATZ
OK
--> Sending: ATQ0 V1 E1 S0=0 &C1 &D2 +FCLASS=0
ATQ0 V1 E1 S0=0 &C1 &D2 +FCLASS=0
OK
--> Modem initialized.
--> Sending: ATDT#777
--> Waiting for carrier.
ATDT#777
CONNECT 153600
--> Carrier detected. Starting PPP immediately.
--> Starting pppd at Sun Oct 18 17:47:48 2009
--> Pid of pppd: 13130
--> Using interface ppp0
--> local IP address 121.245.189.171
--> remote IP address 172.23.119.14
--> primary DNS address 202.54.29.5
--> secondary DNS address 202.54.10.2
^CCaught signal 2: Attempting to exit gracefully...
--> Terminating on signal 15
--> Connect time 5.1 minutes.
--> Disconnecting at Sun Oct 18 17:52:50 2009

7)Command tail -f /var/log/messages --> Just immediately aft.connection gives following:

binnishah@google:~$ tail -f /var/log/messages
Oct 18 17:47:48 google pppd[13130]: Warning - ***
Oct 18 17:47:49 google pppd[13130]: CHAP authentication succeeded
Oct 18 17:47:49 google pppd[13130]: CHAP authentication succeeded
Oct 18 17:47:49 google pppd[13130]: local IP address 121.245.189.171
Oct 18 17:47:49 google pppd[13130]: remote IP address 172.23.119.14
Oct 18 17:47:49 google pppd[13130]: primary DNS address 202.54.29.5
Oct 18 17:47:49 google pppd[13130]: secondary DNS address 202.54.10.2
Oct 18 17:52:50 google pppd[13130]: Terminating on signal 15
Oct 18 17:52:50 google pppd[13130]: Connect time 5.1 minutes.
Oct 18 17:52:50 google pppd[13130]: Sent 158772 bytes, received 741237 bytes.

8)If you dont want to fall in hassles of pwd ( I wouldn't recommend to do so ,though)

sudo vi /etc/sudoers

# User privilege specification
username machine_name = NOPASSWD: /usr/bin/wvdial

So next time when you give wvdial you dont need to type in password

*For Fedora-11 - TATA Photon Whiz :- ==========================

It came to me as surprise that Fed-11 took it in plug n play ie:- just some tweak with Network manager applet and I was sorted out with live n kicking
tata photon whiz USB Mobile broadband

1)Open Network manager applet
2)In that,there's option of --> Mobile Broadband -->Add ( By default you will have Huawei Technologies or your preferable qualcom or whatever) -->Select it -->Forward -->Country - India -->Forward --> Select Tata Indicom(Plug2Surf) if you have photon whiz -->Forward ->Commit changes by pressing apply
3)In Popup of Editing tata Indicom
Add your username & password
and simply press apply
4)Left click Network manager applet and you will have option of Tata Plug2surf ,select it and you are all set

Hope that helps !!!

*Image courtesy

Determine Grade of steel

noreply@blogger.com (Binita M Shah) — Thu, 08 Oct 2009 09:13:00 +0000

/*A certain grade of steel is graded according to the following conditions:
*1)Hardness must be greater than 50
*2)Carbon content must be less than 0.7
*3)Tensile strength must be greater than 5600
*
*The grades are as follows:
*
*Grade is 10 if all three conditions are met
*Grade is 9 if condition 1 & 2 are met
*Grade is 8 if condition 2 & 3 are met
*Grade is 7 if condition 1 & 3 are met
*Grade is 6 if only one condition is met
*Grade is 5 if none of the conditions are met
*
*Write a program which will require the user to give values of hardness,carbon content and tensile

*strength of the steel under consideration and output the grade of the steel*/

# Solution code :

==========

#include <stdio.h>
int main(void)
{
int hard,ts; // hard = hardness ; ts = tensile strength
float cc; //cc -- Carbon content

printf("\nEnter hardness of steel: ");
scanf("%d",&hard);
printf("\nEnter Carbon content of steel : ");
scanf("%f",&cc);
printf("\nEnter Tensile strenght of steel : ");
scanf("%d",&ts);

if ( (hard > 50) && (cc < 0.7) && (ts > 5600))
printf("Steel is of 10th Grade");
else if ( (hard > 50) && (cc < 0.7))
printf("Steel is of 9th Grade");
else if ( (cc < 0.7) && (ts > 5600 ))
printf("Steel is of 8th Grade");
else if (( hard > 50) && (ts > 5600 ))
printf("Steel is of 7th Grade");
else if ( (hard > 50) || (cc < 0.7) || (ts > 5600))
printf("Steel is of 6th Grade");
else
printf("Steel is of 5th Grade");
return 0;
}

Determine if eligible for premium & Policy

noreply@blogger.com (Binita M Shah) — Thu, 08 Oct 2009 03:34:00 +0000

/*An Insurance company follows rules to calculate premium

1)If a person's health is excellent and the person is btw. 25 & 35 years of age and lives in city and is a male then the premium is Rs 4 per thousand and his policy amount cannot exceed Rs 2 lakhs.

2)If a person satisfies all the above conditions except that the sex is female then the premium is Rs 3 per thousand and her policy amount cannot exceed Rs 1 lakh.

3)If a person's health is poor and the person is btw. 25-35 and lives in village and is male ,the premium is Rs 6 per thousand and his policy cannot exceed Rs 10,000

4)In all other cases the person is not insured

Write a program to output whether the person should be insured or not ,his/her premium rate and maximum amount for which he/she can be insured.*/

#Solution

=======

#include <stdio.h>

int main(void)

{

int age,pre,policy_amt;

char sex,live,health;

printf("Enter your age : ");

scanf("%d",&age);

if ( age <= 35 && age >= 25)

{

printf("\nPl.enter your health status ( h/p- h(healthy),p(poor health): ");

scanf(" %c",&health);

printf("\nDo you live in city/Village(c=city)(v=village): ");

scanf(" %c",&live);

printf("\nAre you Male/Female(m=male,f=female : ");

scanf(" %c",&sex);

if ( health == 'h')

{

if ( sex == 'm'&& live == 'c')

printf("\nYou are opt for Rs 4/- Preminum over 1000 Rs & Policy not greater than 2 lakh");

else if ( sex == 'f'&& live == 'c')

printf("\nYou are opt for Rs 3/- Preminum over 1000 Rs & Policy not greater than 1 lakh");

}

else if ( live == 'v' && sex == 'm')

printf("\nYou are opt for Rs 6/- Preminum over 1000 Rs & Policy not greater than 10,000 Rs/-");

if ( sex == 'm' && live == 'c' && health == 'p')

printf("\nSorry no premium or Policy for you");

if ( sex == 'm' && live == 'v' && health == 'h')

printf("\nSorry no premium or Policy for you");

if ( sex == 'f' && live == 'v' && ((health == 'h') || (health == 'p' )))

printf("\nSorry no premium or Policy for you");

if ( sex == 'f' && live == 'c' && health == 'p')

printf("\nSorry no premium or Policy for you");

}

else

printf("\nYou are not eligible for Premium or Policy");

return 0;

}

Determine character input if its Capital,small,decimal or special character

noreply@blogger.com (Binita M Shah) — Wed, 07 Oct 2009 18:40:00 +0000

/*Any character is entered through the keyboard ,write a program to determine whether the character entered is a capital letter,a small case letter,a digit or a special symbol

Following is Range of Ascii values for various characters:-

Characters Ascii Values

A-Z 65-90

a-z 97-122

0-9 48-57

Special symbols 0-47,58-64,91-96,123-127 */

#1 Solution ( With Value of ASCII characters as integer as input) :-

========================================

#include <stdio.h>
int main(void)
{
int i;
printf("Enter a character to determine its type : ");
scanf("%d",&i);

if ( (i <= 90) && (i >= 65))
printf("\nIts %c whose value is %d ,which belongs to A-Z character type",i,i);
else if ( i <= 122 && i >= 97 )
printf("\nIts %c whose value is %d,which belongs to a-z character type",i,i);
else if ( i <= 57 && i >= 48 )
printf("\nIts %c whose value is %d,which belongs to 0-9 character type",i,i);
else if (( i <= 47 && i >= 0) || ( i <= 64 && i >= 58) || ( i >= 91 && i <= 96) || ( i <= 127 && i >= 123))
printf("\nIts %c whose value is %d,which belongs to specific symbols",i,i);
return 0;
}

#2 Solution ( With ASCII Characters as input ) :-

==============================

#include <stdio.h>
int main(void)
{
char i;

printf("Enter a character to determine its type :");
scanf("%c",&i);

if (( i <= 'Z') && (i >= 'A'))
printf("\nIts %c whose value is %d ,which belongs to A-Z character type",i,i);
else if (( i >= 'a') && (i <= 'z' ))
printf("\nIts %c whose value is %d,which belongs to a-z character type",i,i);
else if ( (i >= '0') && (i <= '9'))
printf("\nIts %c whose value is %d,which belongs to 0-9 character type",i,i);
else
printf("\nIts %c whose value is %d,which belongs to *special symbols*",i,i);
return 0;
}

Calculate gross salary

noreply@blogger.com (Binita M Shah) — Wed, 15 Apr 2009 05:11:00 +0000

/*If his basic salary is less than Rs. 1500, then HRA = 10% of basic
salary and DA = 90% of basic salary. If his salary is either equal to
or above Rs. 1500, then HRA = Rs. 500 and DA = 98% of basic
salary. If the employee's salary is input through the keyboard write
a program to find his gross salary.*/

Solution Code:-
=========

#include <stdio.h>
int main(void)
{
int bs;
float hra,da,gross;
printf("Enter Basic Salary : ");
scanf("%d",&bs);
if ( bs < 1500 )
{
hra = bs * 10 / 100;
da = bs * 90 /100;

}

else
{
hra = 500 ;
da = bs * 98 /100;
}

gross = hra + da + bs ;
printf("\n Your gross salary is %f",gross);
return 0;
}

Print a five digit number by adding one to each of its digits

noreply@blogger.com (Binita M Shah) — Tue, 14 Apr 2009 09:44:00 +0000

/*If a five-digit number is input through the keyboard, write a
program to print a new number by adding one to each of its
digits. For example if the number that is input is 12391 then
the output should be displayed as 23402.*/

Solution Code :-
=========

#include <stdio.h>
int main(void)
{
int i,temp = 0;
printf("Enter a +ve 5 digit number :");
scanf("%d",&i);
if (( i <= 99999 ) && ( i > 9999 ))
{
printf(" %d",(i/10000) + 1);
printf(" %d",((( i/100) % 100)/10) + 1);
printf(" %d",(( i/100) % 10 ) + 1);
printf(" %d",((i % 100) / 10) + 1 );
printf(" %d",(i % 10) + 1);
}
else
printf("\n Pl.enter +ve five digit number");
return 0;
}

Calculate price of single item

noreply@blogger.com (Binita M Shah) — Mon, 13 Apr 2009 01:12:00 +0000

*If the total selling price of 15 items and the total profit earned
on them is input through the keyboard, write a program to
find the cost price of one item.*/

/*Here the query maker ,I suppose seeks for groce price rate of one item ,as groce profit & groce selling price is sought out
sin => single item groce price ; procin => profit on single item ;con => conjugal price (profit + single item price)
*/

Solution Code :-
==========

#include <stdio.h>
int main(void)
{
int price,profit,sin,prosin,con;
printf("Enter price of 15 items : ");
scanf("%d",&price);
printf("\nEnter profit made on 15 items : ");
scanf("%d",&profit);
sin = price / 15 ;
prosin = (profit / 15) - sin;
con = sin + prosin ;
printf("\nSingle item cost is %d",sin);
printf("\nSingle item profit is %d",prosin);
printf("\nSingle item cost price is %d",con);
return 0;
}

Find total number of currency notes of each 10,50,100 denominations

noreply@blogger.com (Binita M Shah) — Sun, 12 Apr 2009 15:35:00 +0000

/*A cashier has currency notes of denominations 10, 50 and
100. If the amount to be withdrawn is input through the
keyboard in hundreds, find the total number of currency notes
of each denomination the cashier will have to give to the
withdrawer.*/

Solution Code:-
=========

#include <stdio.h>
int main(void)
{
int amt;
printf("Enter the amount to withdraw : ");
scanf("%d",&amt);
printf("\nNotes of 100 required are %d", amt/100);
printf("\nWhile Notes of 50 required are %d", ((amt % 100)/50));
printf("\nAnd notes of 10 required are %d",((amt % 100)% 50)/10);
return 0;
}

Percentage of Literate & Illiterate along with men & women in town

noreply@blogger.com (Binita M Shah) — Sun, 12 Apr 2009 15:28:00 +0000

/*In a town, the percentage of men is 52. The percentage of
total literacy is 48. If total percentage of literate men is 35 of
the total population, write a program to find the total number
of illiterate men and women if the population of the town is
80,000*/

Solution Code:-
===========
/*popmen = population of men,popwo = population of women ,literate women = ilwo,ilmen = ill-literate men,limen = literate men,liwo = literate women,li= literate men*/

#include <stdio.h>
int main(void)
{
int popmen,popwo,ilmen,ilwo,li,limen,liwo,total;
popmen = (80000 * 52)/100;
printf("\nTotal population of Men in town is %d out of 80000",popmen);
popwo = (80000 - popmen);
printf("\nTotal population of women in town is %d out of 80000",popwo);
li = ( 80000 * 48)/100;
printf("\nTotal literate population in town is %d",li);
limen = ( popmen * 35 )/100;
printf("\nTotal amount of literate Men are %d",limen);
ilmen = popmen - limen;
printf("\nTotal amount of Ill-literate Men are %d",ilmen);
liwo = li - limen ;
printf("\nTotal amount of Literate women is %d",liwo);
ilwo = popwo - liwo ;
printf("\n Total amount of Ill-literate women is %d",ilwo);

return 0;
}

Calculate percentage of 5 subjects & display Divison resp.

noreply@blogger.com (Binita M Shah) — Sat, 11 Apr 2009 13:47:00 +0000

/*The marks obtained by a student in 5 different subjects are input through keyboard.The student gets a division as per the following rules:

Percentage above or equal to 60 - First division
Per btw 50 and 59 - Second div
per btw 40 and 49-Third div
per less than 40 - Fail */

Solution Code:
=========

#include <stdio.h>
int main(void)
{
int m1,m2,m3,m4,m5,sum,per;
printf("Enter marks for Math : ");
scanf("%d",&m1);
printf("\nEnter marks for Chemistry : ");
scanf("%d",&m2);
printf("\nEnter marks for Biology : ");
scanf("%d",&m3);
printf("\nEnter marks for Physics : ");
scanf("%d",&m4);
printf("\nEnter marks for English : ");
scanf("%d",&m5);
sum = (m1 + m2 + m3 + m4 + m5);
per = (sum * 100 / 500);
printf("\nYou got %d percentage",per);

if ( per >= 60 )
printf("\nFirst Division");

else if (( per <= 59) && ( per >= 50 ))
printf("\nSecond Divison");

else if (( per <= 49 ) && ( per >= 40 ))
printf("\nThird Divison");

else
printf("\nSorry you Failed");
return 0;
}

2nd Solution Code:-
===========

#include
int main(void)
{
int m1,m2,m3,m4,m5,sum,per;
printf("Enter marks for Math : ");
scanf("%d",&m1);
printf("\nEnter marks for Chemistry : ");
scanf("%d",&m2);
printf("\nEnter marks for Biology : ");
scanf("%d",&m3);
printf("\nEnter marks for Physics : ");
scanf("%d",&m4);
printf("\nEnter marks for English : ");
scanf("%d",&m5);
sum = (m1 + m2 + m3 + m4 + m5);
per = (sum * 100 / 500);
printf("\nYou got %d percentage",per);

if ( per >= 60 )
printf("\nFirst Division");
else
{
if ( per >= 50 )
printf("\nSecond Division");

else
{
if ( per >= 40 )
printf("\nThird Division");

else
printf("\nFail");
}
}
return 0;
}

Example of compound statement & nested if

noreply@blogger.com (Binita M Shah) — Sat, 11 Apr 2009 13:31:00 +0000

/*Prompts for and accepts input of an integer.Integer is tested to see that it meets the stated criteria.If it doesn't an error message is issued.If all criteria are met,execution terminates silently*/

*Solution Code:-
===========

#include <stdio.h>
int mod(int i);
int main(void)
{
int i;
printf("Enter an Even number less than 20 : ");
scanf("%d",&i);

if ( i < 20)
{
if ( mod(i))
printf("Oops you entered Odd number %d",i);
else if ( i <= 0 )
printf("Oops you entered number less than or equal to 0 %d",i);
}
else
printf("You entered a number greater than 20");

return 0;
}

int mod(int i)
{
return ( i % 2 );
}

Plays a one-time guessing game with user.User enters a number which is compared with target

noreply@blogger.com (Binita M Shah) — Sat, 11 Apr 2009 05:38:00 +0000

/*Plays a one-time guessing game with the user.The user enters a number,which is compared with TARGET.The computer issues a diagnostic message & then the correct result*/

Solution Code:-
=========

#include <stdio.h>
#define TARGET 17
int test(int i,int target);
int main(void)

{
int i;
printf("Enter target number : ");
scanf("%d",&i);
test( i,TARGET);
return 0;
}

void test(int i,int target)
{
if ( i > target)
printf("\nTarget number is smaller than %d,try again",i);
else if ( i < target)
printf("\nTarget number is greater than %d,try again",i);
else if ( i == target )
printf("\nFinally you could make it");

}