C Tutor...

Program to determine the given input is a capital letter, small letter, digit or special symbol.

infocomputers108@gmail.com (pankaj a.h.) — Fri, 06 Nov 2009 14:53:00 +0000

Program to determine the given input is a capital letter, small letter, digit or special symbol.



#include 

int main(void)
{
 char ch;

 printf( "\nEnter a character : " );
 scanf("%c", &ch);


 if(ch >= 'A' && ch <= 'Z')      /* Capital Letter */  
{   
printf( "\nCapital Letter" );  
}  
else if(ch >= 'a' && ch <= 'z') /* Small Letter */  
{   
printf( "\nSmall Letter" );  
}  
else if(ch >= '0' && ch <= '9')  /* Digit */  
{   
printf( "\nDigit" );  
}  
else  
{   
printf( "\nSpecial Symbol" );  
}    
return 0;
}

A program to implement the binary search algorithm

infocomputers108@gmail.com (pankaj a.h.) — Fri, 06 Nov 2009 14:49:00 +0000

A program to implement the binary search algorithm.


#include 

void binary_search(const int *, const int, const int);

int main(void)
{
  int arr[1000], i, v, cnt;

  /* Store the values in the array */
  for( i = 0; i < found =" 0;" fi="first" mi="milldle,li=" n =" 0;" fi =" 0;" li =" sz"> p[li])
  {
      printf( "\n%d not found in the array", val);
      printf( "\nNo of attempts = 1" );
  }
  else
  {
      printf( "\nAttempts\tFirst index\tLast index\tMiddle index\tarr[mi]" );
      while(1)
      {
          n++;
          /* Calculate middle index */
          mi = (fi + li) / 2;

          if( mi == fi || mi == li )
              break; /* Processing complete */

          printf( "\n\t%d\t%d\t\t%d\t\t%d\t\t%d", n, fi, li, mi, p[mi] );
          if(val == p[mi] )
          {
              found = 1;
              break;
          }

          if(val < li =" mi;"> p[mi])
          {
              fi = mi;
              continue;
          }
      }  /*End of while loop */
      if(found)
      {
          printf( "\n%d found in the array", val);
          printf( "\nNo of attempts = %d", n );
      }
      else
      {
          printf( "\n%d NOT found in the array", val);
          printf( "\nNo of attempts = %d", n );
      }
  } /*End of else */
}

Understanding the concept of code blocks

infocomputers108@gmail.com (pankaj a.h.) — Fri, 06 Nov 2009 14:45:00 +0000

Understanding the concept of code blocks.


#include 

int main(void)
{
  int num = 100;

  {                        // beginning of a code block
      int var = 200;      // local variable of this block

      /* inner block or nested block can access variable
      declared in the    outer block */
      printf("\nInner block 1: num = %d var = %d", num, var);

      // char ch;            // error! In C variable declarations should
                          // appear at the top of the block
  }                        // end of a code block

   // var = 300;                // error! var is not accessible here

  {
      /* variable declared in an inner block can have the same
      name as that declared in an outer block */

      int num = 500;

      printf("\nInner block 2: num = %d", num);
  }

  printf("\nOuter block : num = %d", num);

  return 0;
}

Program to show Study of bitwise operators.

infocomputers108@gmail.com (pankaj a.h.) — Fri, 06 Nov 2009 14:43:00 +0000

Program to show Study of bitwise operators.


#include 

int main(void)
{
   unsigned int n = 2;

   printf( "\nn      = %u", n );
   printf( "\nn << 2 = %u", n << 2 );    
printf( "\nn >> 2 = %u", n >> 2 );
   printf( "\nn & 3  = %u", n & 3 );
   printf( "\nn | 3  = %u", n | 3 );
   printf( "\nn ^ 3  = %u", n ^ 3 );
   printf( "\n~n     = %u", ~n );

   return 0;
}

Program to Find the length of a given string.

infocomputers108@gmail.com (pankaj a.h.) — Fri, 06 Nov 2009 14:35:00 +0000

Program to Find the length of a given string.



#include 

int main(void)
{
   char str[80];
   int len;

   printf("\nEnter a string : ");
   gets(str);

   for(len = 0 ; str[len] != '\0' ; len++)

   printf("\nLength of the string is %d", len);

   return 0;
}

Program to find a ASCII value of the given char.

infocomputers108@gmail.com (pankaj a.h.) — Fri, 06 Nov 2009 14:32:00 +0000

Program to find a ASCII value of the given char


#include 

int main(void)
{
   char ch;

   printf("\nEnter a character : ");
   scanf("%c", &ch);

   printf("\nCharacter = %c  ASCII Value = %d", ch, ch);

   return 0;
}

Program to store a list by using 2D arrays

infocomputers108@gmail.com (pankaj a.h.) — Fri, 06 Nov 2009 14:30:00 +0000

Program to store a list by using 2D arrays


int main(void)
{
 /* names can store 3 names i.e. 1 name per row */
 char names[3][20] = { "Ajay", "Vijay", "Sanjay" };
 int i;

 printf( "\nDisplaying names : " );
 for(i = 0 ; i < 3 ; i++)   
printf("\n%s", names[i]);   
return 0;

}

Program to show 3D array Demo.

infocomputers108@gmail.com (pankaj a.h.) — Fri, 06 Nov 2009 14:29:00 +0000

Program to show 3D array Demo.



#include 

int main(void)
{
   int arr[2][3][4], i, j, k;

   for(i = 0 ; i < 2 ; i++)        
for(j = 0 ; j < 3 ; j++)             
for(k = 0 ; k < 4 ; k++)                
arr[i][j][k] = i + j + k;     
printf("\nDisplaying 3D array :");    
for(i = 0 ; i < 2 ; i++)   
{        
printf("\nRow %d", i + 1);       
for(j = 0 ; j < 3 ; j++)        
{            
printf("\tColumn %d\n\t\tCells: ", j + 1);                
for(k = 0 ; k < 4 ; k++)                    
(" %d ", arr[i][j][k]);            
printf("\n");        
}    
}    
return 0;
}

Program to show Study of 2D Array Demo.

infocomputers108@gmail.com (pankaj a.h.) — Fri, 06 Nov 2009 14:27:00 +0000

Program to show Study of 2D Array Demo.



#include 

int main(void)
{
 int arr[3][2]; /* Array representing a matrix of 3 rows and 2 cols */
 int i, j;

 /* Assigning values to array elements */
 arr[0][0] = 10; arr[0][1] = 20;
 arr[1][0] = 30; arr[1][1] = 40;
 arr[2][0] = 50; arr[2][1] = 60;

 printf( "\nDisplaying array elements : " );
 for(i = 0 ; i < 3 ; i++)  
{   
printf("\n");   
for(j = 0 ; j < 2 ; j++)    
printf("%d\t", arr[i][j]);  
}   
return 0;
}

Program to show array of pointers

infocomputers108@gmail.com (pankaj a.h.) — Fri, 06 Nov 2009 14:26:00 +0000

Program to show array of pointers


#include 

int main(void)
{
 float *ap[5], n1, n2, n3, n4, n5;
 int x;

 ap[0] = &n1;
 ap[1] = &n2;
 ap[2] = &n3;
 ap[3] = &n4;
 ap[4] = &n5;

 for(x = 0 ; x < 5 ; x++)  
{   
*ap[x] = (x + 1) / 10.0;  
}   
printf("\n%f\t%f\t%f\t%f\t%f", n1, n2, n3, n4, n5);   
return 0;
}

Menu based program which allows users to calculate the area of Shapes

infocomputers108@gmail.com (pankaj a.h.) — Fri, 06 Nov 2009 14:22:00 +0000

Menu based program which allows users to calculate the area of Shapes.



#include 

int main(void)
{
 char choice;

 do
 {
  
printf("\n\'C\'ircle\n\'T\'riangle\n\'R\'ectangle\n\'S\'quare\n\'E\'xit\nChoice :");
  fflush(stdin);
  scanf("%c", &choice);

  switch(choice)
  {
   case 'c':
   case 'C':
   {
    float radius;
    printf("Enter the radius :");
    scanf("%f", &radius);
    printf("\nArea of circle is %f", 3.14 * radius * radius);
    printf("\nPerimeter of circle is %f", 2 * 3.14 * radius);
    break;
   }
   case 't':
   case 'T':
   {
    float base, ht;
    printf("Enter the base and height :");
    scanf("%f%f", &base, &ht);
    printf("\nArea of triangle is %f", 0.5 * base * ht);
    break;
   }
   case 'r':
   case 'R':
   {
    float length, breadth;
    printf("Enter the length and breadth :");
    scanf("%f%f", &length, &breadth);
    printf("\nArea of rectangle is %f", length * breadth);
    printf("\nPerimeter of rectangle is %f", 2 * (length + breadth));
    break;
   }
   case 's':
   case 'S':
   {
    float side;
    printf("Enter the side :");
    scanf("%f", &side);
    printf("\nArea of square is %f", side * side);
    printf("\nPerimeter of square is %f", 4 * side);
    break;
   }
   default :
    printf("\nInvalid choice");
  }
 }while(choice != 'E' && choice != 'e');

 return 0;
}

Create a 10 element array of integers and count the number of odd and even values in it.

infocomputers108@gmail.com (pankaj a.h.) — Fri, 06 Nov 2009 14:06:00 +0000

Create a 10 element array of integers and count the number of odd and even values in it.



#include 
int main(void)
{
 int arr[10], i, odd, even;

 printf("\nEnter ten integer values : ");
 for(i = 0 ; i < 10; i++)   
scanf("%d", &arr[i]);   for(odd = even = i = 0; i < 10; i++)  
{   
if(arr[i] % 2 == 0)
even++;   
else odd++;  
}   
printf("\nTotal even values is %d\nTotal odd values is %d", even, odd);   
return 0;
}

Program to show implementation of singly linkedlist

infocomputers108@gmail.com (pankaj a.h.) — Fri, 06 Nov 2009 14:01:00 +0000

Program to show implementation of singly linked list



/* linklist.c */
/* implementation of singly linkedlist */
#include
#include
#include "linklist.h"

void release(linkedlist *lp)
{
 while(lp -> count > 0)
 del(lp, lp -> count);
}

node **goto_node(linkedlist *lp, int pos)
{
 node *n = lp -> base, **curr = &(lp -> base);
 if(pos <> lp -> count)
 return NULL;

 while(pos > 0)
 {
  curr = &(n -> next);
  n = n -> next;
  pos--;
 }
 return curr;
}

int append(linkedlist *lp, char *data)
{
 node **curr = goto_node(lp, lp -> count);
 *curr = (node *) malloc(sizeof(node));
 if(*curr == NULL)
 return FALSE;

 strcpy((*curr) -> name, data);
 (*curr) -> next = NULL;
 lp -> count++;
 return TRUE;
}

int insert(linkedlist *lp, int pos, char *data)
{
 node **curr = goto_node(lp, pos - 1), *tmp;
 if(curr == NULL)
  return FALSE;
 tmp = *curr;
 *curr = (node *) malloc(sizeof(node));
 if(*curr == NULL)
 return FALSE;

 strcpy((*curr) -> name, data);
 (*curr) -> next = tmp;
 lp -> count++;
 return TRUE;
}

int del(linkedlist *lp, int pos)
{
 node **curr = goto_node(lp, pos - 1), *tmp;
 if(curr == NULL)
  return FALSE;
 tmp = *curr;
 free(*curr);
 *curr = tmp -> next;
 lp -> count--;
 return TRUE;
}

void show(linkedlist *lp)
{
 node *n = lp -> base;
 while(n != NULL)
 {
  printf("\n%s", n -> name);
  n = n -> next;
 }
}

int main(void)
{
 int choice, pos;
 char value[80];
 linkedlist l = { NULL, 0 };
 do
 {
  printf("\n ** SINGLE LINKED LIST **");
  printf("\n1. Add\n2. Insert\n3. Remove\n4. Show\n5. Exit\nOption [1 - 5] ? ");
  scanf("%d",&choice);
  switch(choice)
  {
   case 1:
    printf("\nName :");
    fflush(stdin);
    gets(value);
    if(!append(&l, value))
     printf( "\nNode creation failed" );
    else
     printf( "\nNew node created successfully" );
    break;
   case 2:
    printf("\nInsert position ? " );
    scanf( "%d", &pos );
    printf("\nEnter value :");
    fflush(stdin);
    gets(value);
    if(!insert(&l, pos, value))
     printf( "\nNode insertion failed" );
    else
     printf( "\nNode inserted successfully" );
    break;
   case 3:
    printf("\nDelete position ? " );
    scanf( "%d", &pos );
    if(!del( &l, pos ))
     printf( "\nNode removal failed" );
    else
     printf("\nNode removed successfully");
    break;
   case 4:
    show(&l);
    break;
   case 5:
    release(&l);
    break;
  }
 }while(choice != 5);

 return SUCCESS;
}

program to create a 10 element array of integers and search for a value in it.

infocomputers108@gmail.com (pankaj a.h.) — Wed, 04 Nov 2009 07:45:00 +0000

program to create a 10 element array of integers and search for a value in it.



#include 

int main(void)
{
 int arr[10], i, val, n;

 printf("\nEnter ten integer values : ");
 for(i = 0 ; i < 10 ; i++ )
  scanf("%d", &arr[i]);

 printf("\nEnter value to search : ");
 scanf("%d", &val);

 /* Search the value in the array */
 n = 0;
 for(i = 0 ; i < 10 ; i++)
 {
  n++;
  if(arr[i] == val)
   break;
 }
 if(i == 10)
 {
  printf("\n%d not found in the array", val);
  printf("\nNo of attempts = %d", n);
 }
 else
 {
  printf("\n%d found in the array", val);
  printf("\nNo of attempts = %d", n);
 }

 return 0;
}

Program to count the number of capital letters, small letters, digits and special symbols in given String

infocomputers108@gmail.com (pankaj a.h.) — Wed, 04 Nov 2009 07:43:00 +0000


/* Take input into a string and count the number of capital letters,
small letters, digits and special symbols in it. */

#include 

int main(void)
{
 char str[80];
 int x, cap, small, dig, sym;

 printf("\nEnter a string : ");
 gets(str);

 x = cap = small = dig = sym = 0;

 for( ; str[x] != '\0' ; x++)
 {
  if(str[x] >= 'A' && str[x] <= 'Z') cap++;
  else if(str[x] >= 'a' && str[x] <= 'z') small++;
  else if(str[x] >= '0' && str[x] <= '9')  dig++;
  else sym++;

 }

 printf("\nCapital letters %d\nSmall letters %d", cap, small);
 printf("\nDigits %d\nSpecial symbols %d", dig, sym);

 return 0;
}

Program to Find the absolute value of an integer taken as input.

infocomputers108@gmail.com (pankaj a.h.) — Wed, 04 Nov 2009 07:40:00 +0000



/* absolute.c */
/* Find the absolute value of an integer taken as input.  */

#include 

int main(void)
{
int num;

printf("\nEnter a number : ");
scanf("%d" ,&num);

if(num <>

Program to Show implementation of singly linkedlist

infocomputers108@gmail.com (pankaj a.h.) — Wed, 04 Nov 2009 07:36:00 +0000


/* linklist.c */
/* implementation of singly linkedlist */
#include
#include
#include "linklist.h"

void release(linkedlist *lp)
{
    while(lp -> count > 0)
    del(lp, lp -> count);
}

node **goto_node(linkedlist *lp, int pos)
{
    node *n = lp -> base, **curr = &(lp -> base);
    if(pos <> lp -> count)
    return NULL;

    while(pos > 0)
    {
        curr = &(n -> next);
        n = n -> next;
        pos--;
    }
    return curr;
}

int append(linkedlist *lp, char *data)
{
    node **curr = goto_node(lp, lp -> count);
    *curr = (node *) malloc(sizeof(node));
    if(*curr == NULL)
    return FALSE;

    strcpy((*curr) -> name, data);
    (*curr) -> next = NULL;
    lp -> count++;
    return TRUE;
}

int insert(linkedlist *lp, int pos, char *data)
{
    node **curr = goto_node(lp, pos - 1), *tmp;
    if(curr == NULL)
        return FALSE;
    tmp = *curr;
    *curr = (node *) malloc(sizeof(node));
    if(*curr == NULL)
    return FALSE;

    strcpy((*curr) -> name, data);
    (*curr) -> next = tmp;
    lp -> count++;
    return TRUE;
}

int del(linkedlist *lp, int pos)
{
    node **curr = goto_node(lp, pos - 1), *tmp;
    if(curr == NULL)
    return FALSE;
    tmp = *curr;
    free(*curr);
    *curr = tmp -> next;
    lp -> count--;
    return TRUE;
}

void show(linkedlist *lp)
{
    node *n = lp -> base;
    while(n != NULL)
    {
        printf("\n%s", n -> name);
        n = n -> next;
    }
}

int main(void)
{
    int choice, pos;
    char value[80];
    linkedlist l = { NULL, 0 };
    do
    {
    printf("\n ** SINGLE LINKED LIST **");
    printf("\n1. Add\n2. Insert\n3. Remove\n4. Show\n5. Exit\nOption [1 - 5]

? ");
        scanf("%d",&choice);
        switch(choice)
        {
            case 1:
                printf("\nName :");
                fflush(stdin);
                gets(value);
                if(!append(&l, value))
                    printf( "\nNode creation failed" );
                else
                    printf( "\nNew node created successfully" );
                break;
            case 2:
                printf("\nInsert position ? " );
                scanf( "%d", &pos );
                printf("\nEnter value :");
                fflush(stdin);
                gets(value);
                if(!insert(&l, pos, value))
                    printf( "\nNode insertion failed" );
                else
                    printf( "\nNode inserted successfully" );
                break;
            case 3:
                printf("\nDelete position ? " );
                scanf( "%d", &pos );
                if(!del( &l, pos ))
                    printf( "\nNode removal failed" );
                else
                    printf("\nNode removed successfully");
                break;
            case 4:
                show(&l);
                break;
            case 5:
                release(&l);
                break;
        }
    }while(choice != 5);

    return SUCCESS;
}

Program to Find Quality of Steel and give Grades

infocomputers108@gmail.com (pankaj a.h.) — Mon, 02 Nov 2009 06:36:00 +0000

A certain grade of steel is graded according to the following conditions:

1)Hardness must be greater than 50
2)Carbon content must be less than 0.7
3)Tensile strength must be greater than 5600

The grades are as follows:
Grade is 10 if all three conditions are met
Grade is 9 if (1) and (2) are met
Grade is 8 if (2) and (3) are met
Grade is 7 if (1) and (3) are met
Grade is 6 if only one condition is met
Grade is 5 if none of the conditions is met

Write a program which will require the user to give the values of hardness,
carbon content and tensile strength of the steel under consideration and output
the grade of the steel.



#include
main()
{
int hardness, ts, grade;

float carbon;

printf("Enter the values of hardness, tensile strength and carbon content in the steel:");
scanf("%d %d %f", &hardness, &ts, &carbon);

if ((hardness>50) && (carbon<0.7)>5600))

printf("Grade 10");
else if ((hardness>50) && (carbon<0.7))
printf("Grade 9"); else if ((carbon<0.7)>5600))

printf("Grade 8");
else if ((hardness>50) && (ts>5600))

printf("Grade 7");
else if ((hardness>50) || (carbon<0.7)>5600))

printf("Grade 6");
else
printf("Grade 5");

}

Program To Calculate Insurance using Logical Operators.

infocomputers108@gmail.com (pankaj a.h.) — Mon, 02 Nov 2009 06:33:00 +0000

Program To Calculate Insurance using Logical Operators.



#include
main()
{
int age,premium, max_amount;

char health, location, sex;


printf("Enter Health - g for good / b for bad\nEnter Location - c for city / v for village");

printf("\nEnter sex - m for male / f for female");

printf("\nEnter the health, age, location and sex of the person:");

scanf ("%c %d %c %c", &health, &age, &location, &sex);



if ((health=='g') && ((age>=25)&&(age<=35)) && (location=='c') && (sex=='m')) 
{
premium=4; max_amount=2;
printf("This person is insured.\nThe payable premium is Rs. %d per thousand\n and the max policy amount is Rs. %d Lakhs", premium, max_amount); 
} 
else
if ((health=='g') && ((age>=25)&&(age<=35)) && (location=='c') && (sex=='f')) 
{
premium=3;
max_amount=1;
printf("This person is insured.\nThe payable premium is Rs. %d per thousand\nand the max policy amount is Rs. %d Lakhs", premium, max_amount); 
} 
else
if((health=='b') && ((age>=25)&&(age<=35)) && (location=='v') && (sex=='m')) 
{
premium=6;
max_amount=10000;
printf("This person is insured.\nThe payable premium is Rs. %d per thousand \nand the max policy amount is Rs. %d ", premium, max_amount); 
} 
else
{
printf("This person is not insured.");
} 
}

Program to Find Character Group using ASCII And Conditional Operator.

infocomputers108@gmail.com (pankaj a.h.) — Mon, 02 Nov 2009 06:30:00 +0000


#include
main()
{
char charac;


printf("Enter the character to be Find:");
scanf("%c", &charac);

((charac>=97) && (charac<=122))?(printf("\nLower Case")):(printf("\nNot a Lower Case character"));

/*For detection of Special Symbols*/

(((charac>=0) && (charac<=47)) || ((charac>=58) && (charac<=64))|| ((charac>=91) && (charac<=96))|| ((charac>=123) && (charac<=127)))? (printf("\nSpecial Symbol")):(printf("\nNot a Special Symbol"));

}

Program to Reverse the number and check for Equality.

infocomputers108@gmail.com (pankaj a.h.) — Mon, 02 Nov 2009 06:24:00 +0000

Program to Reverse the number and check for Equality.



#include
main()
{

int last_digit, number, next_digit, rev_num;

printf ("Enter the five-digit number that has to be reversed and checked for equality:");

scanf("%d", &number);

last_digit = number - ((number / 10) * 10); /*units place*/

rev_num = last_digit; /* 5 */

next_digit = (number / 10) - ((number / 100) * 10); /*tenth's place*/

rev_num = (rev_num * 10) + next_digit; /*54*/

next_digit = (number / 100) - ((number / 1000) * 10); /*hundred's place*/

rev_num = (rev_num * 10) + next_digit; /*543*/

next_digit = (number / 1000) - ((number / 10000) * 10); /*thousand's place*/

rev_num = (rev_num * 10) + next_digit; /*5432*/

next_digit = (number / 10000) - ((number / 100000) * 10); /*ten thousand's place*/

rev_num = (rev_num * 10) + next_digit; /*54321*/

printf ("The Reversed Number is: %d",rev_num);

if (rev_num==number)

{
printf("\nEntered number and reversed number are equal\n");
}
else

{
printf("\nEntered number and reversed number are not equal\n");
}
}

Program to calculate Gross Salary using if-else statement

infocomputers108@gmail.com (pankaj a.h.) — Mon, 02 Nov 2009 06:22:00 +0000

In a company if an employee is paid as under:

If his basic salary is less than Rs. 1500, then HRA=10% of basic salary and DA=90% of basic salary.
If his salary is either equal to or above Rs. 1500, then HRA = Rs. 500 and DA = 98% of basic salary.
If the employee's salary is input through the keyboard write a program to find his gross salary.



#include
main()
{

float bs, gs, da, hra;

printf ("Enter basic salary:");

scanf ("%f", &bs);

if (bs<1500)

{
hra=bs*10/100;
da=bs*90/100;

}
else
{
hra=500;
da=bs*98/100;

}

gs=bs + hra + da;

printf ("gross salary = Rs. %f", gs);
}

Program To Calculate Discount using 'if' statement.

infocomputers108@gmail.com (pankaj a.h.) — Mon, 02 Nov 2009 06:20:00 +0000




#include
main()

{
int qty,dis=0; /*initializing is required as if tot<1000, then discount is 0*/
float rate, tot;

printf ("Enter quantity and rate: ");
scanf ("%d %f", &qty, &rate);

if (qty>1000)
dis=10;

tot=(qty*rate) - (qty*rate*dis/100);

printf("Total expenses = Rs. %f", tot);

}

Program To Calculate Driver insurance using if-else statement

infocomputers108@gmail.com (pankaj a.h.) — Mon, 02 Nov 2009 06:18:00 +0000

A company insures its drivers in the following cases:
- If the driver is married.
- If the driver is unmarried, male and above 30 years of age.
- If the driver is unmarried, female and above 25 years of age.

In all the other cases, the driver is not insured.
If the marital status, sex and age of the driver are the inputs,
write a program to determine whether the driver is insured or not.


#include
main()
{

char sex,ms;
int age;

printf ("Enter age, sex, marital status:");

scanf ("%d %c %c", &age, &sex, &ms);

if (ms=='M')

printf ("The driver is insured");
else
{
if (sex=='M')

{
if (age>30)
printf ("Driver is insured");

else
printf ("Driver is not insured");
}
else
{

if (age>25)
printf ("Driver is insured");
else
printf ("Driver is not insured");

}
}
}

Program To Calculate Employees Bonus In C

infocomputers108@gmail.com (pankaj a.h.) — Mon, 02 Nov 2009 06:16:00 +0000



#include
main ()
{

int bonus, cy, yoj, yr_of_ser;

printf ("Enter current year and year of joining: ");

scanf ("%d %d", &cy, &yoj);

yr_of_ser = cy - yoj;

if (yr_of_ser>3)
{
bonus = 2500;

printf ("Bonus = Rs. %d", bonus);
}
}