<?xml version='1.0' encoding='UTF-8'?><rss xmlns:atom="http://www.w3.org/2005/Atom" xmlns:openSearch="http://a9.com/-/spec/opensearchrss/1.0/" xmlns:blogger="http://schemas.google.com/blogger/2008" xmlns:georss="http://www.georss.org/georss" xmlns:gd="http://schemas.google.com/g/2005" xmlns:thr="http://purl.org/syndication/thread/1.0" version="2.0"><channel><atom:id>tag:blogger.com,1999:blog-3004824991035263317</atom:id><lastBuildDate>Mon, 07 Oct 2024 03:08:30 +0000</lastBuildDate><category>Construcciones gráficas fundamentales</category><category>Geometría</category><title>Técnicamente Dibujando</title><description></description><link>http://tecnicamentedibujando.blogspot.com/</link><managingEditor>noreply@blogger.com (zake_ajl)</managingEditor><generator>Blogger</generator><openSearch:totalResults>8</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>25</openSearch:itemsPerPage><item><guid isPermaLink="false">tag:blogger.com,1999:blog-3004824991035263317.post-3424726077821499880</guid><pubDate>Thu, 11 Jun 2009 11:52:00 +0000</pubDate><atom:updated>2009-06-11T04:52:57.290-07:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">Construcciones gráficas fundamentales</category><category domain="http://www.blogger.com/atom/ns#">Geometría</category><title>Arco capaz</title><description>Arco capaz de un segmento &lt;b&gt;AB&lt;/b&gt; para un ángulo &lt;b&gt;alfa&lt;/b&gt; , es el lugar geométrico de los puntos de plano desde los cuales se ve el segmento &lt;b&gt;AB&lt;/b&gt; bajo un ángulo&amp;nbsp; &lt;b&gt;alfa&lt;/b&gt;&lt;br /&gt;
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&lt;b&gt;1º&lt;/b&gt; Mediatriz del segmento &lt;b&gt;AB&lt;/b&gt;&lt;br /&gt;
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&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhYvATqZSidwSdX85h0o59zRFHDAijntv-fVpoo33RyoIgddikI657AGXQSASnLLlDSU864wHaA__b2NgiGWMJB4DFCcLyznPfKVs6eODmm6L2yXpS1Vnx_8kXnHP3cZWIqdUPSJQ4Om-gd/s1600-h/arco1.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhYvATqZSidwSdX85h0o59zRFHDAijntv-fVpoo33RyoIgddikI657AGXQSASnLLlDSU864wHaA__b2NgiGWMJB4DFCcLyznPfKVs6eODmm6L2yXpS1Vnx_8kXnHP3cZWIqdUPSJQ4Om-gd/s400/arco1.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;
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&lt;b&gt;2º&lt;/b&gt; Semirrecta que partiendo del extremo&lt;b&gt; A&lt;/b&gt; forme con el segmento &lt;b&gt;AB&lt;/b&gt; un ángulo igual a &lt;b&gt;alfa menos 90º&lt;/b&gt;&lt;br /&gt;
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&lt;b&gt;3º&lt;/b&gt; Arco con centro en la intersección de la mediatriz con la semirrecta y radio hasta uno de los extremos&lt;br /&gt;
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&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgQCpI-MEnuTFFuaTOYe5Z3TO2VE73jWxyhyoeT0ZjOcihv9ksf1uFD6FKTBuc-Tk1ouPRbtiV55tku0rAA_ks1qU4wcDwB3-wICtVVAqSssgJKxFhn4ezuDK3gyDD5TThxWKLlZolBoSFW/s1600-h/arco3.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgQCpI-MEnuTFFuaTOYe5Z3TO2VE73jWxyhyoeT0ZjOcihv9ksf1uFD6FKTBuc-Tk1ouPRbtiV55tku0rAA_ks1qU4wcDwB3-wICtVVAqSssgJKxFhn4ezuDK3gyDD5TThxWKLlZolBoSFW/s400/arco3.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;</description><link>http://tecnicamentedibujando.blogspot.com/2009/06/arco-capaz.html</link><author>noreply@blogger.com (zake_ajl)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjy8GAipPEQJrvffm3bpaNMYr3yKZtogrlwtR1IiV7lmp_ze71x0TPW17cCR7t9kGRFJZMJiknM46a43mBtdScalfnQeiGK7D3tGWS1tiynRJ9fsgkvyoQyGoX28r_ynR5wkJJwp2ECtuQo/s72-c/arco.png" height="72" width="72"/><thr:total>1</thr:total></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-3004824991035263317.post-2428397292550101228</guid><pubDate>Thu, 11 Jun 2009 11:26:00 +0000</pubDate><atom:updated>2009-06-11T04:26:47.376-07:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">Construcciones gráficas fundamentales</category><category domain="http://www.blogger.com/atom/ns#">Geometría</category><title>Determinación del centro de un arco cualquiera de circunferencia</title><description>&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgOueZHb8tlyBTnz049PkzHRsYiXPUdtb62CAY44GM37KsIVGC4vbqXay6Oa8ScBv6b1EDRbGSqbed219oZ5dJ6AlLv4WkvcX81WotTKRxMjTQeOgiaSYshvi8Fyej_fP9EBRgecodUq_72/s1600-h/arco.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgOueZHb8tlyBTnz049PkzHRsYiXPUdtb62CAY44GM37KsIVGC4vbqXay6Oa8ScBv6b1EDRbGSqbed219oZ5dJ6AlLv4WkvcX81WotTKRxMjTQeOgiaSYshvi8Fyej_fP9EBRgecodUq_72/s400/arco.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;
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&lt;b&gt;1º&lt;/b&gt; Cuerdas arbitrarias &lt;b&gt;AB&lt;/b&gt; y &lt;b&gt;CD&lt;/b&gt; arbitrarias&lt;br /&gt;
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&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhrlKGo_PeqBFAFvDQXUYNwcvsXzOrx5xuaYEUioNKho9sELP9xZqWwkDuOZmJxtj2c7057ot5V_QF5LcFTmPyDjZ7SVCvWEF5McJbGkJsgxayRpaF9OxsJWsin04wM8mr7JbCH4MyizCoA/s1600-h/arco1.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhrlKGo_PeqBFAFvDQXUYNwcvsXzOrx5xuaYEUioNKho9sELP9xZqWwkDuOZmJxtj2c7057ot5V_QF5LcFTmPyDjZ7SVCvWEF5McJbGkJsgxayRpaF9OxsJWsin04wM8mr7JbCH4MyizCoA/s400/arco1.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;
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&lt;b&gt;2º&lt;/b&gt; Mediatrices de las cuerdas &lt;b&gt;AB&lt;/b&gt; y &lt;b&gt;CD&lt;/b&gt;&lt;br /&gt;
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&lt;b&gt;3º&lt;/b&gt; La intersección de ambas mediatrices nos permite obtener el centro &lt;b&gt;O&lt;/b&gt; del arco&lt;br /&gt;
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&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiN6wqKeeJdYjm41VgD-wNqhU_UvMgw-JsTXAUEv000axTyaJajkIUSxB7gs65XwHw3ovtYIolDCWPlcnpf_Rlyqq8Me9Gbrgl9uNh0V07GKeZgf2hS4_gDBgYv44CIRL42DKmfRNqCeIaf/s1600-h/arco3.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiN6wqKeeJdYjm41VgD-wNqhU_UvMgw-JsTXAUEv000axTyaJajkIUSxB7gs65XwHw3ovtYIolDCWPlcnpf_Rlyqq8Me9Gbrgl9uNh0V07GKeZgf2hS4_gDBgYv44CIRL42DKmfRNqCeIaf/s400/arco3.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;</description><link>http://tecnicamentedibujando.blogspot.com/2009/06/determinacion-del-centro-de-un-arco.html</link><author>noreply@blogger.com (zake_ajl)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgOueZHb8tlyBTnz049PkzHRsYiXPUdtb62CAY44GM37KsIVGC4vbqXay6Oa8ScBv6b1EDRbGSqbed219oZ5dJ6AlLv4WkvcX81WotTKRxMjTQeOgiaSYshvi8Fyej_fP9EBRgecodUq_72/s72-c/arco.png" height="72" width="72"/><thr:total>0</thr:total></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-3004824991035263317.post-4161766124265982036</guid><pubDate>Thu, 11 Jun 2009 11:02:00 +0000</pubDate><atom:updated>2009-06-11T04:02:21.442-07:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">Construcciones gráficas fundamentales</category><category domain="http://www.blogger.com/atom/ns#">Geometría</category><title>División de una ángulo recto en tres partes iguales</title><description>&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi9LsqmpYtQh-KFKTbSoj21fgq-uiclk9wd-yECTj0zKDRVd6HseGIj3bHPgAKrP6cy6cekfx5Hemo3re4Ik1Rxx_e7DSTTYi4bI1EGw6LZF9vvJfsuLvxRj00JaxIM8897bxgq26NGfTPf/s1600-h/angulo.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi9LsqmpYtQh-KFKTbSoj21fgq-uiclk9wd-yECTj0zKDRVd6HseGIj3bHPgAKrP6cy6cekfx5Hemo3re4Ik1Rxx_e7DSTTYi4bI1EGw6LZF9vvJfsuLvxRj00JaxIM8897bxgq26NGfTPf/s400/angulo.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;
&lt;b&gt;1º&lt;/b&gt; Arco de circunferencia de centro &lt;b&gt;V&lt;/b&gt; y radio arbitrario, obteniendo los puntos &lt;b&gt;A&lt;/b&gt; y &lt;b&gt;B&lt;/b&gt;&lt;br /&gt;
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&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg8jA0rkNjG0AKZ1ijUq5CJWotOnty8gl8hY_S3CFse3v98-XX96i3akDTRtLTUy46TcUuL_TCV59S8lzkbjD4J9DkXNricuNi8uOJlWRduOJXgxnQ1aQSDLHTFsQIwWf8KU-Cto5mlb6gA/s1600-h/angulo1.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg8jA0rkNjG0AKZ1ijUq5CJWotOnty8gl8hY_S3CFse3v98-XX96i3akDTRtLTUy46TcUuL_TCV59S8lzkbjD4J9DkXNricuNi8uOJlWRduOJXgxnQ1aQSDLHTFsQIwWf8KU-Cto5mlb6gA/s400/angulo1.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;
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&lt;b&gt;2º&lt;/b&gt; Arco de circunferencia de centro &lt;b&gt;B&lt;/b&gt; y mismo radio que el arco anterior, obteniendo el punto &lt;b&gt;C&lt;/b&gt;&lt;br /&gt;
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&lt;b&gt;3º&lt;/b&gt; Recta que une los puntos &lt;b&gt;V&lt;/b&gt; y&lt;b&gt;C&lt;/b&gt;&lt;br /&gt;
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&lt;b&gt;4º&lt;/b&gt; Bisectriz de ángulo formado por &lt;b&gt;VC&lt;/b&gt; y &lt;b&gt;VB&lt;/b&gt;&lt;br /&gt;
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&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjLenA6mpqOwR3qORm-j2uJny8232tZfkyMiYLIjnsm3EJbjF8-z6pvfuPBrUAq2LuFZQ0uD01Nx34juQ8WoCfpyrV-henoh7kl0C9j0aHYSEquR4MooHn_DPJDrUMHudNpGH30zsdqGYLj/s1600-h/angulo4.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjLenA6mpqOwR3qORm-j2uJny8232tZfkyMiYLIjnsm3EJbjF8-z6pvfuPBrUAq2LuFZQ0uD01Nx34juQ8WoCfpyrV-henoh7kl0C9j0aHYSEquR4MooHn_DPJDrUMHudNpGH30zsdqGYLj/s400/angulo4.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;</description><link>http://tecnicamentedibujando.blogspot.com/2009/06/division-de-una-angulo-recto-en-tres.html</link><author>noreply@blogger.com (zake_ajl)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi9LsqmpYtQh-KFKTbSoj21fgq-uiclk9wd-yECTj0zKDRVd6HseGIj3bHPgAKrP6cy6cekfx5Hemo3re4Ik1Rxx_e7DSTTYi4bI1EGw6LZF9vvJfsuLvxRj00JaxIM8897bxgq26NGfTPf/s72-c/angulo.png" height="72" width="72"/><thr:total>0</thr:total></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-3004824991035263317.post-1033428457401742437</guid><pubDate>Fri, 05 Jun 2009 19:56:00 +0000</pubDate><atom:updated>2009-06-05T12:56:43.990-07:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">Construcciones gráficas fundamentales</category><category domain="http://www.blogger.com/atom/ns#">Geometría</category><title>Transportar un ángulo</title><description>&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjncXs4pRAM2hoWMtNoyZV5sKqZBWuY7nvCRN0uJfVAHcUaD6KlsRllHzdGSINaPfodnrSQQWzjlrFLh-ddw1jFH7FbiKLXrnEOMX2MAbv7jkJXgpBznZV7-bHVLhrT8egPlCTFU9111TnE/s1600-h/angulo.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjncXs4pRAM2hoWMtNoyZV5sKqZBWuY7nvCRN0uJfVAHcUaD6KlsRllHzdGSINaPfodnrSQQWzjlrFLh-ddw1jFH7FbiKLXrnEOMX2MAbv7jkJXgpBznZV7-bHVLhrT8egPlCTFU9111TnE/s320/angulo.png&quot; /&gt;&lt;/a&gt;&amp;nbsp;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: left;&quot;&gt;&lt;b&gt;1º&lt;/b&gt; Arco de circunferencia de centro &lt;b&gt;V&lt;/b&gt; y radio arbitrario, obteniendo los puntos &lt;b&gt;A &lt;/b&gt;y &lt;b&gt;B&lt;/b&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: left;&quot;&gt;&lt;/div&gt;&lt;br /&gt;
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&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg70EEWEN-QEiW1zTu7Hm-ifkM__33USqUzjJgNwCJtRJMH_l2MZ0ttmYakgTKK8MGsezPv_jrEwdSI-mTI0eI3qO3Fc_Lt4mGk06HliLIzu0Pzy3hK8mISYI8v8sYFt-11jIwWWlF51RCc/s1600-h/angulo1.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEg70EEWEN-QEiW1zTu7Hm-ifkM__33USqUzjJgNwCJtRJMH_l2MZ0ttmYakgTKK8MGsezPv_jrEwdSI-mTI0eI3qO3Fc_Lt4mGk06HliLIzu0Pzy3hK8mISYI8v8sYFt-11jIwWWlF51RCc/s400/angulo1.png&quot; /&gt;&lt;/a&gt;&amp;nbsp;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: left;&quot;&gt;&lt;/div&gt;&lt;b&gt;2º&lt;/b&gt; Arco de circunferencia de centro &lt;b&gt;V&#39;&lt;/b&gt; y radio &lt;b&gt;VA&lt;/b&gt;, obteniendo el punto &lt;b&gt;C&lt;/b&gt;&lt;br /&gt;
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&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpNlfrqE_6VvgjOQIhkI5yZoN7lhKmiPbz4sGmAYV-oitsbFbO_bPZDgGYUm7vtWspyX6gmu4S44W-ufAgV7DVc9PDOsK9jb7c39AtBHABtLhOEhDHw6UQFO1sof-pAnRfzau8qQb_J5-W/s1600-h/angulo2.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgpNlfrqE_6VvgjOQIhkI5yZoN7lhKmiPbz4sGmAYV-oitsbFbO_bPZDgGYUm7vtWspyX6gmu4S44W-ufAgV7DVc9PDOsK9jb7c39AtBHABtLhOEhDHw6UQFO1sof-pAnRfzau8qQb_J5-W/s400/angulo2.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;
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&amp;nbsp; &lt;br /&gt;
&lt;b&gt;3º&lt;/b&gt; Arco de circunferencia de centro &lt;b&gt;A&lt;/b&gt; y radio &lt;b&gt;AB&lt;/b&gt;&lt;br /&gt;
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&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEio6V7gsG6UhmXRefrt5jf7BwS40PRxSr_SlLFUEKPFewJbjXo4rklrdBiGzzfZN8PmsYMPM6EpcVAxLM1jcY3rW_rUfF9zzHteVAHSJM5fhS6h7CvkqWK2PxdOqfG_DzI_21quRSOXhnLP/s1600-h/angulo3.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEio6V7gsG6UhmXRefrt5jf7BwS40PRxSr_SlLFUEKPFewJbjXo4rklrdBiGzzfZN8PmsYMPM6EpcVAxLM1jcY3rW_rUfF9zzHteVAHSJM5fhS6h7CvkqWK2PxdOqfG_DzI_21quRSOXhnLP/s400/angulo3.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;
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&lt;b&gt;4º&lt;/b&gt; Arco de circunferencia de centro &lt;b&gt;C&lt;/b&gt; y radio &lt;b&gt;AB&lt;/b&gt;, obteniendo el punto &lt;b&gt;D&lt;/b&gt;.&lt;br /&gt;
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&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEirisqhMoMLSCQ_4idEw2r8u823MHFXcA4nzGj-8zqiaQ3TwNJBMUVyYb6O4izWYOXlJP2iCvNR4ra9GffPvwHOAd2kS8S9xHIiPibkntO31Wg2Jr9QwZLh7yw85olmbD2oQkPWlXIwZ-V8/s1600-h/angulo4.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEirisqhMoMLSCQ_4idEw2r8u823MHFXcA4nzGj-8zqiaQ3TwNJBMUVyYb6O4izWYOXlJP2iCvNR4ra9GffPvwHOAd2kS8S9xHIiPibkntO31Wg2Jr9QwZLh7yw85olmbD2oQkPWlXIwZ-V8/s400/angulo4.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;
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&lt;b&gt;5º&lt;/b&gt; Semirrecta &lt;b&gt;VD&lt;/b&gt; obteniendo el ángulo&lt;br /&gt;
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&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjpuAeeZgGIqzs6cq3S7EsAGdDxEG_vP1zId4jDi-kWJgwjCURSB3vMrF6023Bfj8y9ldGqie7uWeN_0Daf6N4IGuMjtlgawjRJGjXS7SupLiekvsUSBmyVeX-x9Otj7iaIu3gMW5TozTXc/s1600-h/angulo5.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjpuAeeZgGIqzs6cq3S7EsAGdDxEG_vP1zId4jDi-kWJgwjCURSB3vMrF6023Bfj8y9ldGqie7uWeN_0Daf6N4IGuMjtlgawjRJGjXS7SupLiekvsUSBmyVeX-x9Otj7iaIu3gMW5TozTXc/s400/angulo5.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;</description><link>http://tecnicamentedibujando.blogspot.com/2009/06/transportar-un-angulo.html</link><author>noreply@blogger.com (zake_ajl)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEjncXs4pRAM2hoWMtNoyZV5sKqZBWuY7nvCRN0uJfVAHcUaD6KlsRllHzdGSINaPfodnrSQQWzjlrFLh-ddw1jFH7FbiKLXrnEOMX2MAbv7jkJXgpBznZV7-bHVLhrT8egPlCTFU9111TnE/s72-c/angulo.png" height="72" width="72"/><thr:total>0</thr:total></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-3004824991035263317.post-3761029567821548232</guid><pubDate>Fri, 05 Jun 2009 19:43:00 +0000</pubDate><atom:updated>2009-06-05T12:44:58.618-07:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">Construcciones gráficas fundamentales</category><category domain="http://www.blogger.com/atom/ns#">Geometría</category><title>Trazado de la perpendicular a una recta por uno de sus extremos</title><description>&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiGjiHy8xNP-zqsf7WIqE56eeq9rSDSTVw1ZSMR1zKFPhEjb7jqn95HdLlGz0BBAIXyTARLG7pXr2VAftHnHg7U9nSDYPNGOhQTj-SNln4nor8OKnGuGctfAI3UIZeBXkGdoaBKq-p_zCBw/s1600-h/recta4.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiGjiHy8xNP-zqsf7WIqE56eeq9rSDSTVw1ZSMR1zKFPhEjb7jqn95HdLlGz0BBAIXyTARLG7pXr2VAftHnHg7U9nSDYPNGOhQTj-SNln4nor8OKnGuGctfAI3UIZeBXkGdoaBKq-p_zCBw/s400/recta4.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;
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&lt;b&gt;1º&lt;/b&gt; Prolongamos el segmento por el extremo &lt;b&gt;B&lt;/b&gt;&lt;br /&gt;
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&lt;p&gt;&lt;/p&gt;&lt;p&gt;&lt;/p&gt;&lt;br /&gt;
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&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi8RDUogMJZs6oNxY_5Rs42P9xcNkIyib7Xa2XBGr74FvlH0QxcBDfXXIR5ODZSZ93s84hHthj5IK9Uiv5PKEVtuxS4LIVDv7CLUP-hzx6AL_tFa1DzxiT52ZgVR3B6Dv-l36EZluq2UhBH/s1600-h/recta5.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi8RDUogMJZs6oNxY_5Rs42P9xcNkIyib7Xa2XBGr74FvlH0QxcBDfXXIR5ODZSZ93s84hHthj5IK9Uiv5PKEVtuxS4LIVDv7CLUP-hzx6AL_tFa1DzxiT52ZgVR3B6Dv-l36EZluq2UhBH/s320/recta5.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;
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&lt;p&gt;&lt;/p&gt;&lt;p&gt;&lt;/p&gt;&lt;br /&gt;
&lt;b&gt;2º&lt;/b&gt; Arcos de circunferencia de centro &lt;b&gt;B&lt;/b&gt; y radio arbitrario obteniendo el segmento &lt;b&gt;CD&lt;/b&gt;&lt;br /&gt;
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&lt;p&gt;&lt;/p&gt;&lt;br /&gt;
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&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEj4nv0JwmJjoIBv8cIR7Sev3JIQH3Qc07gW2xUjlaqObRh8EOzjrQCQl_d9H4Yh-LJCM2FLMgNehe8OLoQXBgNkWV_Z5hxKLX7CuGPlDOEiesCQU4pFYZnWnhvXk7JjROuqSPHFbd4yGmUr/s1600-h/recta6.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEj4nv0JwmJjoIBv8cIR7Sev3JIQH3Qc07gW2xUjlaqObRh8EOzjrQCQl_d9H4Yh-LJCM2FLMgNehe8OLoQXBgNkWV_Z5hxKLX7CuGPlDOEiesCQU4pFYZnWnhvXk7JjROuqSPHFbd4yGmUr/s320/recta6.png&quot; /&gt;&lt;/a&gt;&amp;nbsp;&lt;/div&gt;&lt;br /&gt;
&lt;p&gt;&lt;/p&gt;&lt;p&gt;&lt;/p&gt;&lt;br /&gt;
&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: left;&quot;&gt;&lt;b&gt;3º&lt;/b&gt; Mediatriz del segmento &lt;b&gt;CD&lt;/b&gt; &lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: left;&quot;&gt;&lt;/div&gt;&lt;br /&gt;
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&lt;p&gt;&lt;/p&gt;&lt;p&gt;&lt;/p&gt;&lt;div style=&quot;text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEivvGFO85D1BcFXvGTxYY4e8ZO-NxqFkTV2m-BhFkP37SLd0cxr6AYa3jMUWP4bdntlJ5T5OV0BP4aJ_XbeuR2hJSGozZNUVfJLKS5d6FG6_3gX4cXUKzhUZ48n21hAikN-EXkkbrpIL4ba/s1600-h/recta7.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEivvGFO85D1BcFXvGTxYY4e8ZO-NxqFkTV2m-BhFkP37SLd0cxr6AYa3jMUWP4bdntlJ5T5OV0BP4aJ_XbeuR2hJSGozZNUVfJLKS5d6FG6_3gX4cXUKzhUZ48n21hAikN-EXkkbrpIL4ba/s400/recta7.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: left;&quot;&gt;&lt;/div&gt;&lt;br /&gt;
&lt;p&gt;&lt;/p&gt;&lt;p&gt;&lt;/p&gt;</description><link>http://tecnicamentedibujando.blogspot.com/2009/06/trazado-de-la-perpendicular-una-recta.html</link><author>noreply@blogger.com (zake_ajl)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiGjiHy8xNP-zqsf7WIqE56eeq9rSDSTVw1ZSMR1zKFPhEjb7jqn95HdLlGz0BBAIXyTARLG7pXr2VAftHnHg7U9nSDYPNGOhQTj-SNln4nor8OKnGuGctfAI3UIZeBXkGdoaBKq-p_zCBw/s72-c/recta4.png" height="72" width="72"/><thr:total>0</thr:total></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-3004824991035263317.post-7474866726816658480</guid><pubDate>Tue, 02 Jun 2009 14:31:00 +0000</pubDate><atom:updated>2009-06-02T07:35:24.290-07:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">Construcciones gráficas fundamentales</category><category domain="http://www.blogger.com/atom/ns#">Geometría</category><title>Trazado de perpendiculares a una recta por un punto interior</title><description>&lt;p&gt;&lt;/p&gt;&lt;br /&gt;&lt;p&gt;&lt;/p&gt;&lt;br /&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;&quot; style=&quot;clear: both; font-family: Arial,Helvetica,sans-serif; text-align: left;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;&quot; style=&quot;clear: both; font-family: Arial,Helvetica,sans-serif; text-align: left;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;&quot; style=&quot;clear: both; font-family: Arial,Helvetica,sans-serif; text-align: left;&quot;&gt;&lt;b&gt;1º &lt;/b&gt;Arcos de centro &lt;b&gt;P&lt;/b&gt; y radio arbitrario, obteniendo los puntos &lt;b&gt;A&lt;/b&gt; y &lt;b&gt;B&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;/b&gt;&lt;/div&gt;&lt;div class=&quot;&quot; style=&quot;clear: both; font-family: Arial,Helvetica,sans-serif; text-align: left;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;&quot; style=&quot;clear: both; font-family: Arial,Helvetica,sans-serif; text-align: left;&quot;&gt;&lt;b&gt;&lt;br /&gt;&lt;/b&gt;&lt;/div&gt;&lt;div class=&quot;&quot; style=&quot;clear: both; font-family: Arial,Helvetica,sans-serif; text-align: left;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;&quot; style=&quot;clear: both; font-family: Arial,Helvetica,sans-serif; text-align: left;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; font-family: Arial,Helvetica,sans-serif; text-align: left;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; font-family: Arial,Helvetica,sans-serif; text-align: left;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; font-family: Arial,Helvetica,sans-serif; text-align: left;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEinHVErBHMq-2n1f8IYbGzzVPjfZUqG2qw4U7UeP12lHr8EmNWLJjsqAyDDn1qLJZvDZqmMStA35_c3_lItJs68yljgY3HKp_Rc8onPD8lie7O7eVQ7tl4C62PbPetFgudQxxTcKDeF9d25/s1600-h/recta.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEinHVErBHMq-2n1f8IYbGzzVPjfZUqG2qw4U7UeP12lHr8EmNWLJjsqAyDDn1qLJZvDZqmMStA35_c3_lItJs68yljgY3HKp_Rc8onPD8lie7O7eVQ7tl4C62PbPetFgudQxxTcKDeF9d25/s400/recta.png&quot; border=&quot;0&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;div class=&quot;&quot; style=&quot;clear: both; font-family: Arial,Helvetica,sans-serif; text-align: left;&quot;&gt;&lt;b&gt;  &lt;/b&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; font-family: Arial,Helvetica,sans-serif; text-align: center;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;/div&gt;&lt;br /&gt;&lt;br /&gt;&lt;div class=&quot;&quot; style=&quot;clear: both; text-align: left;&quot;&gt;&lt;/div&gt;&lt;br /&gt;&lt;div class=&quot;&quot; style=&quot;clear: both; text-align: left;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;&quot; style=&quot;clear: both; text-align: left;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;&quot; style=&quot;clear: both; text-align: left;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhHbTUYEUHCS5dAY6Bj9eClsyiqo9xcmtKrCtmvy7J-h8k0Y5HDRhIZC_mDYnGoZYvyZm0HoCqoe8bsfprbA0sI4CtvNzlQFoU4Wy6kOzU-Z-_18o_-2_V3lM_4Ha1zhjoQcqnUVBcvvdaf/s1600-h/recta1.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhHbTUYEUHCS5dAY6Bj9eClsyiqo9xcmtKrCtmvy7J-h8k0Y5HDRhIZC_mDYnGoZYvyZm0HoCqoe8bsfprbA0sI4CtvNzlQFoU4Wy6kOzU-Z-_18o_-2_V3lM_4Ha1zhjoQcqnUVBcvvdaf/s400/recta1.png&quot; border=&quot;0&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;div class=&quot;&quot; style=&quot;clear: both; text-align: left;&quot;&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;span style=&quot;font-family:Arial,Helvetica,sans-serif;&quot;&gt;&lt;b&gt;2º&lt;/b&gt; Mediatriz del segmento &lt;b&gt;AB&lt;/b&gt;&lt;/span&gt;&lt;/div&gt;&lt;div class=&quot;&quot; style=&quot;clear: both; text-align: left;&quot;&gt;&lt;span style=&quot;font-family:Arial,Helvetica,sans-serif;&quot;&gt;&lt;b&gt; &lt;/b&gt; &lt;/span&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEidhzqr0hsQp4eEbhD4El6E_EkpWRArVbPaaixLwMoadSjXQ15Kz3NU9miGJm54R6fmcBXpa52XJrYb0zG3XDzKRrSw00qVhgi-CYILiMfmreQNJAozrdn-DTDyTFX5dA1fTsf172pjdapr/s1600-h/recta2.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEidhzqr0hsQp4eEbhD4El6E_EkpWRArVbPaaixLwMoadSjXQ15Kz3NU9miGJm54R6fmcBXpa52XJrYb0zG3XDzKRrSw00qVhgi-CYILiMfmreQNJAozrdn-DTDyTFX5dA1fTsf172pjdapr/s400/recta2.png&quot; border=&quot;0&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;&lt;/p&gt;&lt;br /&gt;&lt;/p&gt;</description><link>http://tecnicamentedibujando.blogspot.com/2009/06/trazado-de-perpendiculares-una-recta_02.html</link><author>noreply@blogger.com (zake_ajl)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEinHVErBHMq-2n1f8IYbGzzVPjfZUqG2qw4U7UeP12lHr8EmNWLJjsqAyDDn1qLJZvDZqmMStA35_c3_lItJs68yljgY3HKp_Rc8onPD8lie7O7eVQ7tl4C62PbPetFgudQxxTcKDeF9d25/s72-c/recta.png" height="72" width="72"/><thr:total>0</thr:total></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-3004824991035263317.post-7113098627969576082</guid><pubDate>Tue, 02 Jun 2009 14:08:00 +0000</pubDate><atom:updated>2009-06-02T07:12:30.726-07:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">Construcciones gráficas fundamentales</category><category domain="http://www.blogger.com/atom/ns#">Geometría</category><title>Trazado de perpendiculares a una recta por un punto exterior</title><description>&lt;p&gt;&lt;/p&gt;&lt;br /&gt;&lt;p&gt;&lt;/p&gt;&lt;br /&gt;&lt;br /&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhwJSvzfsFZ68zAPZnpmhBXT2-3L6x7TwKdi8q56ShT_ntcaNhYiwQoOV7AEfzMX7GuGEKSi0Nsnr5ZbU24KaAJluLT1UgRXl5tWImD_-nPVfqwrM53aiUty9AAWfGUQGJA9zkZNEfHc4m0/s1600-h/perpendicular1.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhwJSvzfsFZ68zAPZnpmhBXT2-3L6x7TwKdi8q56ShT_ntcaNhYiwQoOV7AEfzMX7GuGEKSi0Nsnr5ZbU24KaAJluLT1UgRXl5tWImD_-nPVfqwrM53aiUty9AAWfGUQGJA9zkZNEfHc4m0/s400/perpendicular1.png&quot; border=&quot;0&quot; /&gt;&lt;/a&gt; &lt;/div&gt;&lt;div class=&quot;&quot; style=&quot;clear: both; text-align: center;&quot;&gt;  &lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; font-family: Arial,Helvetica,sans-serif; text-align: left;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; font-family: Arial,Helvetica,sans-serif; text-align: left;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;&quot; style=&quot;clear: both; font-family: Arial,Helvetica,sans-serif; text-align: left;&quot;&gt;&lt;b&gt;&lt;br /&gt;&lt;br /&gt;1º&lt;/b&gt; Arco de circunferencia de centro&lt;b&gt; P &lt;/b&gt;y radio arbitrario mayor que la distancia del punto &lt;b&gt;P&lt;/b&gt; a la recta, obteniendo el segmento &lt;b&gt;AB&lt;/b&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; font-family: Arial,Helvetica,sans-serif; text-align: left;&quot;&gt;&lt;/div&gt;&lt;div style=&quot;text-align: center;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; font-family: Arial,Helvetica,sans-serif; text-align: left;&quot;&gt;&lt;/div&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEja4CbFVy-btl_rmt-lP_HgT_H_aFmZDPqHrVyocdKZMbdt61nX7lGdgPvVhTLswfk8UOQ6MvlS13vhNixJfT1FG9-IeTjRz11KuI1K1Ya-XboOx2z7mwOUGbn0N_BXUKlAslHhc0f1_rC9/s1600-h/recta.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEja4CbFVy-btl_rmt-lP_HgT_H_aFmZDPqHrVyocdKZMbdt61nX7lGdgPvVhTLswfk8UOQ6MvlS13vhNixJfT1FG9-IeTjRz11KuI1K1Ya-XboOx2z7mwOUGbn0N_BXUKlAslHhc0f1_rC9/s400/recta.png&quot; border=&quot;0&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;b style=&quot;font-family: Arial,Helvetica,sans-serif;&quot;&gt;2º&lt;/b&gt;&lt;span style=&quot;font-family:Arial,Helvetica,sans-serif;&quot;&gt; Mediatriz de segmento &lt;/span&gt;&lt;b style=&quot;font-family: Arial,Helvetica,sans-serif;&quot;&gt;AB&lt;/b&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi-ZZRMn6v7xHdev3jTNAAsCIoU-08O59tX2SNgZ6o4GLZ645kiAvHQ3f_byRhNJCKml21jF620QpE4x6-wCDCtgCxpmztA_fNphVasKFrxOkNhPMYfYtq1Wpb9ylafwSIgqpLdtnqmfUOU/s1600-h/recta1.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEi-ZZRMn6v7xHdev3jTNAAsCIoU-08O59tX2SNgZ6o4GLZ645kiAvHQ3f_byRhNJCKml21jF620QpE4x6-wCDCtgCxpmztA_fNphVasKFrxOkNhPMYfYtq1Wpb9ylafwSIgqpLdtnqmfUOU/s400/recta1.png&quot; border=&quot;0&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;&lt;/p&gt;&lt;br /&gt;&lt;/p&gt;</description><link>http://tecnicamentedibujando.blogspot.com/2009/06/trazado-de-perpendiculares-una-recta.html</link><author>noreply@blogger.com (zake_ajl)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEhwJSvzfsFZ68zAPZnpmhBXT2-3L6x7TwKdi8q56ShT_ntcaNhYiwQoOV7AEfzMX7GuGEKSi0Nsnr5ZbU24KaAJluLT1UgRXl5tWImD_-nPVfqwrM53aiUty9AAWfGUQGJA9zkZNEfHc4m0/s72-c/perpendicular1.png" height="72" width="72"/><thr:total>2</thr:total></item><item><guid isPermaLink="false">tag:blogger.com,1999:blog-3004824991035263317.post-5766054011955139458</guid><pubDate>Mon, 01 Jun 2009 20:45:00 +0000</pubDate><atom:updated>2009-06-01T13:45:17.706-07:00</atom:updated><category domain="http://www.blogger.com/atom/ns#">Construcciones gráficas fundamentales</category><category domain="http://www.blogger.com/atom/ns#">Geometría</category><title>Trazado de la bisectriz de un ángulo</title><description>&lt;span style=&quot;font-family: Arial,Helvetica,sans-serif;&quot;&gt;&lt;b&gt;La bisectriz&lt;/b&gt; de un ángulo es la semirrecta que partiendo del vertice divide al ángulo en dos partes iguales&lt;/span&gt;&lt;br /&gt;
&lt;br /&gt;
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&lt;div style=&quot;text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEio3tMUNnP5FJAUQFVGgcAKL7Jo5YjU7mMbXoXp7OaGgFPJfboSGFkod6zTLlucXRC6WCMgEdDhqNMOw1TFQ2sq8NRSrAE-RvUg66jVQAUs8itu0TUp9a2W2ZTyD094SuKvsPxzNJ0GzUuH/s1600-h/angulo1.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEio3tMUNnP5FJAUQFVGgcAKL7Jo5YjU7mMbXoXp7OaGgFPJfboSGFkod6zTLlucXRC6WCMgEdDhqNMOw1TFQ2sq8NRSrAE-RvUg66jVQAUs8itu0TUp9a2W2ZTyD094SuKvsPxzNJ0GzUuH/s400/angulo1.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;
&lt;span style=&quot;font-family: Arial,Helvetica,sans-serif;&quot;&gt;&lt;b&gt;1º&lt;/b&gt; Trazamos un arco de circunferencia de centro &lt;b&gt;V&lt;/b&gt; y radio arbitrario obteniendo los puntos &lt;b&gt;A&lt;/b&gt; y &lt;b&gt;B&lt;/b&gt;&lt;/span&gt;&lt;br /&gt;
&lt;br /&gt;
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&lt;div style=&quot;text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgkTbFscMdOdTecy_9sSIMhLMmCXLUkrY7EfSaUihxFnn8SgWui4UqN9XqB_z4xlU6BJcWx1sLAl3DqMkm3giZelOT4nPjsirLcz6XxMOCEJSJ2W40YtrEQStU04R4qtmbM9xTQgNhNZq4i/s1600-h/angulo2.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEgkTbFscMdOdTecy_9sSIMhLMmCXLUkrY7EfSaUihxFnn8SgWui4UqN9XqB_z4xlU6BJcWx1sLAl3DqMkm3giZelOT4nPjsirLcz6XxMOCEJSJ2W40YtrEQStU04R4qtmbM9xTQgNhNZq4i/s400/angulo2.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;
&lt;span style=&quot;font-family: Arial,Helvetica,sans-serif;&quot;&gt;&lt;b&gt;2º&lt;/b&gt; Trazamos un arcos de radio arbitrario r con centros en&lt;b&gt; A&lt;/b&gt; y &lt;b&gt;B&lt;/b&gt;, obteniendo el punto &lt;b&gt;C&lt;/b&gt;&lt;/span&gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEj0H6IWcs5bIE8b7sbPfiFOnwxs31BbFx7_OJuAwm7-C7eXWlfkjsqe3WRY4x0_t9tLoOs_sy5P3tO5-wKjx3LDAF-QPR9bbovrNvXQxdWeFu8wPTPfLa_Pm1hPnxXPUImccmhfGQMOFcED/s1600-h/angulo3.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEj0H6IWcs5bIE8b7sbPfiFOnwxs31BbFx7_OJuAwm7-C7eXWlfkjsqe3WRY4x0_t9tLoOs_sy5P3tO5-wKjx3LDAF-QPR9bbovrNvXQxdWeFu8wPTPfLa_Pm1hPnxXPUImccmhfGQMOFcED/s320/angulo3.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
&lt;b&gt;3º&lt;/b&gt; Recta que pasa por los puntos &lt;b&gt;V&lt;/b&gt; y &lt;b&gt;C&lt;/b&gt;&lt;br /&gt;
&lt;br /&gt;
&lt;br /&gt;
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&lt;div class=&quot;separator&quot; style=&quot;clear: both; text-align: center;&quot;&gt;&lt;a href=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiaGuM6kV1ORzGtOOOazQ0r7eGAOZDAzcThZR-QVaqAxn0Y-FoNpFRR1WH1IPaKL6F5HqdKyfMy5HlS9tEOrXQf_XqJjGJWbcwSACjOXTLefM4T3MxRiIZLZ1CMJGk4VV5neHR3eaAYycdW/s1600-h/angulo4.png&quot; imageanchor=&quot;1&quot; style=&quot;margin-left: 1em; margin-right: 1em;&quot;&gt;&lt;img border=&quot;0&quot; src=&quot;https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEiaGuM6kV1ORzGtOOOazQ0r7eGAOZDAzcThZR-QVaqAxn0Y-FoNpFRR1WH1IPaKL6F5HqdKyfMy5HlS9tEOrXQf_XqJjGJWbcwSACjOXTLefM4T3MxRiIZLZ1CMJGk4VV5neHR3eaAYycdW/s320/angulo4.png&quot; /&gt;&lt;/a&gt;&lt;/div&gt;&lt;span style=&quot;font-family: Arial,Helvetica,sans-serif;&quot;&gt;&lt;b&gt;&amp;nbsp;&lt;/b&gt;&lt;br /&gt;
&lt;/span&gt;</description><link>http://tecnicamentedibujando.blogspot.com/2009/06/trazado-de-la-bisectriz-de-un-angulo.html</link><author>noreply@blogger.com (zake_ajl)</author><media:thumbnail xmlns:media="http://search.yahoo.com/mrss/" url="https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEio3tMUNnP5FJAUQFVGgcAKL7Jo5YjU7mMbXoXp7OaGgFPJfboSGFkod6zTLlucXRC6WCMgEdDhqNMOw1TFQ2sq8NRSrAE-RvUg66jVQAUs8itu0TUp9a2W2ZTyD094SuKvsPxzNJ0GzUuH/s72-c/angulo1.png" height="72" width="72"/><thr:total>13</thr:total></item></channel></rss>