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    <title>Mathalino.com - Online Engineering Mathematics</title>
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    <title>Example 002 | Components of a Force</title>
    <link>http://feedproxy.google.com/~r/Mathalinocom-OnlineEngineeringMathematics/~3/TK7-HQgUtgk/example-002-components-of-a-force</link>
    <description>&lt;p&gt;&lt;a href="http://feedads.g.doubleclick.net/~a/RCSOB99HwGCq5Sb4xaQfbSSS4fA/0/da"&gt;&lt;img src="http://feedads.g.doubleclick.net/~a/RCSOB99HwGCq5Sb4xaQfbSSS4fA/0/di" border="0" ismap="true"&gt;&lt;/img&gt;&lt;/a&gt;&lt;br/&gt;
&lt;a href="http://feedads.g.doubleclick.net/~a/RCSOB99HwGCq5Sb4xaQfbSSS4fA/1/da"&gt;&lt;img src="http://feedads.g.doubleclick.net/~a/RCSOB99HwGCq5Sb4xaQfbSSS4fA/1/di" border="0" ismap="true"&gt;&lt;/img&gt;&lt;/a&gt;&lt;/p&gt;&lt;div style="width: 224px" class="image-attach-teaser"&gt;&lt;a href="/reviewer/engineering-mechanics/example-002-components-of-a-force"&gt;&lt;img src="http://www.mathalino.com/sites/default/files/images/012-forces-in-xy-plane.jpg" alt="eng-mech 005 Forces in XY plane" title="eng-mech 005 Forces in XY plane"  class="image image-preview " width="224" height="272" /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;!-- google_ad_section_start --&gt;&lt;h3&gt;Problem 002&lt;/h3&gt;
&lt;p&gt;Compute the x and y components of each of the four forces shown in &lt;a href="http://www.mathalino.com/image/eng-mech-005-forces-in-xy-plane"&gt;Fig. P-002&lt;/a&gt;.&lt;/p&gt;
&lt;h4&gt;&amp;nbsp;&lt;/h4&gt;
&lt;!-- google_ad_section_end --&gt;&lt;div class="feedflare"&gt;
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&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/Mathalinocom-OnlineEngineeringMathematics/~4/TK7-HQgUtgk" height="1" width="1"/&gt;</description>
     <comments>http://www.mathalino.com/reviewer/engineering-mechanics/example-002-components-of-a-force#comments</comments>
 <category domain="http://www.mathalino.com/tags/tags/2d-force">2d force</category>
 <category domain="http://www.mathalino.com/tags/tags/components-of-a-force">components of a force</category>
 <category domain="http://www.mathalino.com/tags/tags/vector-notation">vector notation</category>
 <category domain="http://www.mathalino.com/tags/tags/x-component">x-component</category>
 <category domain="http://www.mathalino.com/tags/tags/y-component">y-component</category>
 <enclosure url="http://www.mathalino.com/image/view/868/preview" length="19310" type="image/jpeg" />
 <pubDate>Thu, 18 Mar 2010 15:57:42 +0000</pubDate>
 <dc:creator>Mathalino</dc:creator>
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  <item>
    <title>Example 001 | Components of a Force</title>
    <link>http://feedproxy.google.com/~r/Mathalinocom-OnlineEngineeringMathematics/~3/RwwJRb_7XhY/example-001-components-of-a-force</link>
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&lt;a href="http://feedads.g.doubleclick.net/~a/cTt6drQTgHDzdohTlAFvTv8FpYM/1/da"&gt;&lt;img src="http://feedads.g.doubleclick.net/~a/cTt6drQTgHDzdohTlAFvTv8FpYM/1/di" border="0" ismap="true"&gt;&lt;/img&gt;&lt;/a&gt;&lt;/p&gt;&lt;div style="width: 256px" class="image-attach-teaser"&gt;&lt;a href="/reviewer/engineering-mechanics/example-001-components-of-a-force"&gt;&lt;img src="http://www.mathalino.com/sites/default/files/images/011-force-component-example.jpg" alt="eng-mech 004 Forces in XY Plane" title="eng-mech 004 Forces in XY Plane"  class="image image-preview " width="256" height="285" /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;!-- google_ad_section_start --&gt;&lt;h3&gt;Problem 001&lt;/h3&gt;
&lt;p&gt;Problem Determine the x and y components of the forces shown below in &lt;a href="http://www.mathalino.com/image/eng-mech-004-forces-in-xy-plane"&gt;Fig P-001&lt;/a&gt;.&lt;/p&gt;
&lt;h4&gt;&amp;nbsp;&lt;/h4&gt;
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&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/Mathalinocom-OnlineEngineeringMathematics/~4/RwwJRb_7XhY" height="1" width="1"/&gt;</description>
     <comments>http://www.mathalino.com/reviewer/engineering-mechanics/example-001-components-of-a-force#comments</comments>
 <category domain="http://www.mathalino.com/tags/tags/2d-force">2d force</category>
 <category domain="http://www.mathalino.com/tags/tags/components-of-a-force">components of a force</category>
 <category domain="http://www.mathalino.com/tags/tags/vector-notation">vector notation</category>
 <category domain="http://www.mathalino.com/tags/tags/x-component">x-component</category>
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 <enclosure url="http://www.mathalino.com/image/view/866/preview" length="19454" type="image/jpeg" />
 <pubDate>Thu, 18 Mar 2010 15:15:35 +0000</pubDate>
 <dc:creator>Mathalino</dc:creator>
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  <item>
    <title>Solution to Problem 654 | Deflections in Simply Supported Beams</title>
    <link>http://feedproxy.google.com/~r/Mathalinocom-OnlineEngineeringMathematics/~3/Wwi5ws1YWU0/solution-to-problem-654-deflections-in-simply-supported</link>
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&lt;!-- google_ad_section_start --&gt;&lt;h3&gt;Problem 654&lt;/h3&gt;
&lt;p&gt;For the beam in &lt;a href="http://www.mathalino.com/image/654-simple-beam-subjected-to-rectangular-loading"&gt;Fig. P-654&lt;/a&gt;, find the value of EI&lt;font face="Times New Roman, Times, serif"&gt;&amp;delta;&lt;/font&gt; at 2 ft from R&lt;sub&gt;2&lt;/sub&gt;. (Hint: Draw the reference tangent to the elastic curve at R&lt;sub&gt;2&lt;/sub&gt;.)&lt;/p&gt;
&lt;h4&gt;&amp;nbsp;&lt;/h4&gt;
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&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/Mathalinocom-OnlineEngineeringMathematics/~4/Wwi5ws1YWU0" height="1" width="1"/&gt;</description>
     <comments>http://www.mathalino.com/reviewer/mechanics-and-strength-of-materials/solution-to-problem-654-deflections-in-simply-supported#comments</comments>
 <category domain="http://www.mathalino.com/tags/tags/beam-deflection">beam deflection</category>
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 <enclosure url="http://www.mathalino.com/image/view/864/preview" length="13736" type="image/jpeg" />
 <pubDate>Tue, 16 Mar 2010 08:04:42 +0000</pubDate>
 <dc:creator>Mathalino</dc:creator>
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  <item>
    <title>Solution to Problem 653 | Deflections in Simply Supported Beams</title>
    <link>http://feedproxy.google.com/~r/Mathalinocom-OnlineEngineeringMathematics/~3/hpNii8iBaRc/solution-to-problem-653-deflections-in-simply-supported</link>
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&lt;!-- google_ad_section_start --&gt;&lt;h3&gt;Problem 653&lt;/h3&gt;
&lt;p&gt;Compute the midspan value of EI&lt;font face="Times New Roman, Times, serif"&gt;&amp;delta;&lt;/font&gt; for the beam shown in &lt;a href="http://www.mathalino.com/image/653-simple-beam-with-symmetrically-placed-rectangular-load"&gt;Fig. P-653&lt;/a&gt;. (Hint: Draw the M diagram by parts, starting from midspan toward the ends. Also take advantage of symmetry to note that the tangent drawn to the elastic curve at midspan is horizontal.)&lt;/p&gt;
&lt;h4&gt;&amp;nbsp;&lt;/h4&gt;
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&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/Mathalinocom-OnlineEngineeringMathematics/~4/hpNii8iBaRc" height="1" width="1"/&gt;</description>
     <comments>http://www.mathalino.com/reviewer/mechanics-and-strength-of-materials/solution-to-problem-653-deflections-in-simply-supported#comments</comments>
 <category domain="http://www.mathalino.com/tags/tags/beam-deflection">beam deflection</category>
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 <category domain="http://www.mathalino.com/tags/tags/moment-diagram">moment diagram</category>
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 <pubDate>Tue, 16 Mar 2010 07:02:33 +0000</pubDate>
 <dc:creator>Mathalino</dc:creator>
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  <item>
    <title>Deflections in Simply Supported Beams | Area-Moment Method</title>
    <link>http://feedproxy.google.com/~r/Mathalinocom-OnlineEngineeringMathematics/~3/NBaoVX8N5Qg/deflection-in-simply-supported-beams-area-moment-method</link>
    <description>&lt;p&gt;&lt;a href="http://feedads.g.doubleclick.net/~a/53LK7H_5fPMyv7BtPFzAXnOH2NY/0/da"&gt;&lt;img src="http://feedads.g.doubleclick.net/~a/53LK7H_5fPMyv7BtPFzAXnOH2NY/0/di" border="0" ismap="true"&gt;&lt;/img&gt;&lt;/a&gt;&lt;br/&gt;
&lt;a href="http://feedads.g.doubleclick.net/~a/53LK7H_5fPMyv7BtPFzAXnOH2NY/1/da"&gt;&lt;img src="http://feedads.g.doubleclick.net/~a/53LK7H_5fPMyv7BtPFzAXnOH2NY/1/di" border="0" ismap="true"&gt;&lt;/img&gt;&lt;/a&gt;&lt;/p&gt;&lt;div style="width: 345px" class="image-attach-teaser"&gt;&lt;a href="/reviewer/mechanics-and-strength-of-materials/deflection-in-simply-supported-beams-area-moment-method"&gt;&lt;img src="http://www.mathalino.com/sites/default/files/images/deflection-simply-supported-beam.jpg" alt="Area-moment method of finding deflections in simply supported beam" title="Area-moment method of finding deflections in simply supported beam"  class="image image-preview " width="345" height="233" /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;!-- google_ad_section_start --&gt;&lt;p&gt;The deflection &lt;font face="Times New Roman, Times, serif"&gt;&amp;delta;&lt;/font&gt; at some point B of a simply supported beam can be obtained by the following steps:&lt;/p&gt;
&lt;h4&gt;&amp;nbsp;&lt;/h4&gt;
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&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/Mathalinocom-OnlineEngineeringMathematics/~4/NBaoVX8N5Qg" height="1" width="1"/&gt;</description>
     <comments>http://www.mathalino.com/reviewer/mechanics-and-strength-of-materials/deflection-in-simply-supported-beams-area-moment-method#comments</comments>
 <category domain="http://www.mathalino.com/tags/tags/beam-deflection">beam deflection</category>
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 <pubDate>Mon, 15 Mar 2010 14:42:50 +0000</pubDate>
 <dc:creator>Mathalino</dc:creator>
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  <item>
    <title>Components of a Force</title>
    <link>http://feedproxy.google.com/~r/Mathalinocom-OnlineEngineeringMathematics/~3/DmPcwhaimJc/components-of-a-force</link>
    <description>&lt;p&gt;&lt;a href="http://feedads.g.doubleclick.net/~a/K0BSHCm9JDpLSvveyqru8CvkiFA/0/da"&gt;&lt;img src="http://feedads.g.doubleclick.net/~a/K0BSHCm9JDpLSvveyqru8CvkiFA/0/di" border="0" ismap="true"&gt;&lt;/img&gt;&lt;/a&gt;&lt;br/&gt;
&lt;a href="http://feedads.g.doubleclick.net/~a/K0BSHCm9JDpLSvveyqru8CvkiFA/1/da"&gt;&lt;img src="http://feedads.g.doubleclick.net/~a/K0BSHCm9JDpLSvveyqru8CvkiFA/1/di" border="0" ismap="true"&gt;&lt;/img&gt;&lt;/a&gt;&lt;/p&gt;&lt;div style="width: 272px" class="image-attach-teaser"&gt;&lt;a href="/reviewer/engineering-mechanics/components-of-a-force"&gt;&lt;img src="http://www.mathalino.com/sites/default/files/images/007-components-force-3d-xyz.jpg" alt="eng-mech 003 Components of a Force" title="eng-mech 003 Components of a Force"  class="image image-preview " width="272" height="246" /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;!-- google_ad_section_start --&gt;&lt;p&gt;Forces acting at some angle from the the coordinate axes can be resolved into mutually perpendicular forces called &lt;strong&gt;components&lt;/strong&gt;.  The component of a force parallel to the x-axis is called the x-component, parallel to y-axis the y-component, and so on.&lt;/p&gt;
&lt;h4&gt;&amp;nbsp;&lt;/h4&gt;
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&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/Mathalinocom-OnlineEngineeringMathematics/~4/DmPcwhaimJc" height="1" width="1"/&gt;</description>
     <comments>http://www.mathalino.com/reviewer/engineering-mechanics/components-of-a-force#comments</comments>
 <category domain="http://www.mathalino.com/tags/tags/2d-force">2d force</category>
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 <pubDate>Mon, 15 Mar 2010 08:41:33 +0000</pubDate>
 <dc:creator>Mathalino</dc:creator>
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  <item>
    <title>Resultant of Parallel Force System</title>
    <link>http://feedproxy.google.com/~r/Mathalinocom-OnlineEngineeringMathematics/~3/SBtQbpsJIUs/resultant-of-parallel-force-system</link>
    <description>&lt;p&gt;&lt;a href="http://feedads.g.doubleclick.net/~a/6yoT53LSFjOqN-Ii5P5Ejwvprqg/0/da"&gt;&lt;img src="http://feedads.g.doubleclick.net/~a/6yoT53LSFjOqN-Ii5P5Ejwvprqg/0/di" border="0" ismap="true"&gt;&lt;/img&gt;&lt;/a&gt;&lt;br/&gt;
&lt;a href="http://feedads.g.doubleclick.net/~a/6yoT53LSFjOqN-Ii5P5Ejwvprqg/1/da"&gt;&lt;img src="http://feedads.g.doubleclick.net/~a/6yoT53LSFjOqN-Ii5P5Ejwvprqg/1/di" border="0" ismap="true"&gt;&lt;/img&gt;&lt;/a&gt;&lt;/p&gt;&lt;div style="width: 278px" class="image-attach-teaser"&gt;&lt;a href="/reviewer/engineering-mechanics/resultant-of-parallel-force-system"&gt;&lt;img src="http://www.mathalino.com/sites/default/files/images/003-resultant-parallel-forces.jpg" alt="eng-mech 002 Resultant Coplanar Parallel Forces" title="eng-mech 002 Resultant Coplanar Parallel Forces"  class="image image-preview " width="278" height="222" /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;!-- google_ad_section_start --&gt;&lt;h3&gt;Coplanar Parallel Force System&lt;/h3&gt;
&lt;p&gt;Parallel forces can be in the same or in opposite directions.  The sign of the direction can be chosen arbitrarily, meaning, taking one direction as positive makes the opposite direction negative.  The complete definition of the resultant is according to its magnitude, direction, and line of action.&lt;/p&gt;
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&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/Mathalinocom-OnlineEngineeringMathematics/~4/SBtQbpsJIUs" height="1" width="1"/&gt;</description>
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 <pubDate>Sun, 14 Mar 2010 14:55:24 +0000</pubDate>
 <dc:creator>Mathalino</dc:creator>
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  <item>
    <title>Resultant of Concurrent Force System</title>
    <link>http://feedproxy.google.com/~r/Mathalinocom-OnlineEngineeringMathematics/~3/Xt7Ek350y90/resultant-of-concurrent-force-system</link>
    <description>&lt;p&gt;&lt;a href="http://feedads.g.doubleclick.net/~a/hEvb-n9vuJ8zo1U77nJX_2Ogx3k/0/da"&gt;&lt;img src="http://feedads.g.doubleclick.net/~a/hEvb-n9vuJ8zo1U77nJX_2Ogx3k/0/di" border="0" ismap="true"&gt;&lt;/img&gt;&lt;/a&gt;&lt;br/&gt;
&lt;a href="http://feedads.g.doubleclick.net/~a/hEvb-n9vuJ8zo1U77nJX_2Ogx3k/1/da"&gt;&lt;img src="http://feedads.g.doubleclick.net/~a/hEvb-n9vuJ8zo1U77nJX_2Ogx3k/1/di" border="0" ismap="true"&gt;&lt;/img&gt;&lt;/a&gt;&lt;/p&gt;&lt;div style="width: 499px" class="image-attach-teaser"&gt;&lt;a href="/reviewer/engineering-mechanics/resultant-of-concurrent-force-system"&gt;&lt;img src="http://www.mathalino.com/sites/default/files/images/001-resultant-spatial-concurrent-forces.jpg" alt="eng-mech 001 Resultant of concurrent forces in space" title="eng-mech 001 Resultant of concurrent forces in space"  class="image image-preview " width="499" height="239" /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;!-- google_ad_section_start --&gt;&lt;p&gt;&lt;strong&gt;Resultant&lt;/strong&gt; of a force system is a force or a couple that will have the same effect to the body, both in translation and rotation, if all the forces are removed and replaced by the resultant.&lt;/p&gt;
&lt;h4&gt;&amp;nbsp;&lt;/h4&gt;
&lt;!-- google_ad_section_end --&gt;&lt;div class="feedflare"&gt;
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&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/Mathalinocom-OnlineEngineeringMathematics/~4/Xt7Ek350y90" height="1" width="1"/&gt;</description>
     <comments>http://www.mathalino.com/reviewer/engineering-mechanics/resultant-of-concurrent-force-system#comments</comments>
 <category domain="http://www.mathalino.com/tags/tags/components-of-a-force">components of a force</category>
 <category domain="http://www.mathalino.com/tags/tags/concurrent-forces">concurrent forces</category>
 <category domain="http://www.mathalino.com/tags/tags/coplanar-force">coplanar force</category>
 <category domain="http://www.mathalino.com/tags/tags/direction-cosines">direction cosines</category>
 <category domain="http://www.mathalino.com/tags/tags/non-concurrent-forces">non-concurrent forces</category>
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 <pubDate>Sat, 13 Mar 2010 08:11:10 +0000</pubDate>
 <dc:creator>Mathalino</dc:creator>
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  <item>
    <title>Example 6 | Plane Areas in Polar Coordinates</title>
    <link>http://feedproxy.google.com/~r/Mathalinocom-OnlineEngineeringMathematics/~3/4X_3yU6XiDc/example-6-plane-areas-in-polar-coordinates</link>
    <description>&lt;p&gt;&lt;a href="http://feedads.g.doubleclick.net/~a/ahZ1SPPC1P7km8SRMs5_l5Qbadk/0/da"&gt;&lt;img src="http://feedads.g.doubleclick.net/~a/ahZ1SPPC1P7km8SRMs5_l5Qbadk/0/di" border="0" ismap="true"&gt;&lt;/img&gt;&lt;/a&gt;&lt;br/&gt;
&lt;a href="http://feedads.g.doubleclick.net/~a/ahZ1SPPC1P7km8SRMs5_l5Qbadk/1/da"&gt;&lt;img src="http://feedads.g.doubleclick.net/~a/ahZ1SPPC1P7km8SRMs5_l5Qbadk/1/di" border="0" ismap="true"&gt;&lt;/img&gt;&lt;/a&gt;&lt;/p&gt;&lt;div style="width: 400px" class="image-attach-teaser"&gt;&lt;a href="/reviewer/integral-calculus/example-6-plane-areas-in-polar-coordinates"&gt;&lt;img src="http://www.mathalino.com/sites/default/files/images/016-graph-r2-16cos-theta.jpg" alt="int-016 Area of the graph of r^2 = 16 cos (theta)" title="int-016 Area of the graph of r^2 = 16 cos (theta)"  class="image image-preview " width="400" height="251" /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;!-- google_ad_section_start --&gt;&lt;h3&gt;Example 6&lt;/h3&gt;
&lt;p&gt;What is the area within the curve r&lt;sup&gt;2&lt;/sup&gt; = 16 cos &lt;font face="Times New Roman, Times, serif"&gt;&amp;theta;&lt;/font&gt;?&lt;/p&gt;
&lt;h4&gt;&amp;nbsp;&lt;/h4&gt;
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&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/Mathalinocom-OnlineEngineeringMathematics/~4/4X_3yU6XiDc" height="1" width="1"/&gt;</description>
     <comments>http://www.mathalino.com/reviewer/integral-calculus/example-6-plane-areas-in-polar-coordinates#comments</comments>
 <category domain="http://www.mathalino.com/tags/tags/area-by-integration">area by integration</category>
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 <category domain="http://www.mathalino.com/tags/tags/plane-areas">plane areas</category>
 <category domain="http://www.mathalino.com/tags/tags/polar-area">polar area</category>
 <category domain="http://www.mathalino.com/tags/tags/polar-curves">polar curves</category>
 <enclosure url="http://www.mathalino.com/image/view/853/preview" length="27967" type="image/jpeg" />
 <pubDate>Wed, 10 Mar 2010 07:28:41 +0000</pubDate>
 <dc:creator>Mathalino</dc:creator>
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  <item>
    <title>Example 5 | Plane Areas in Polar Coordinates</title>
    <link>http://feedproxy.google.com/~r/Mathalinocom-OnlineEngineeringMathematics/~3/EBTLLBR3bxY/example-5-plane-areas-in-polar-coordinates</link>
    <description>&lt;p&gt;&lt;a href="http://feedads.g.doubleclick.net/~a/zjqZ-rCM9U70EmpWCw0hWgdDUVA/0/da"&gt;&lt;img src="http://feedads.g.doubleclick.net/~a/zjqZ-rCM9U70EmpWCw0hWgdDUVA/0/di" border="0" ismap="true"&gt;&lt;/img&gt;&lt;/a&gt;&lt;br/&gt;
&lt;a href="http://feedads.g.doubleclick.net/~a/zjqZ-rCM9U70EmpWCw0hWgdDUVA/1/da"&gt;&lt;img src="http://feedads.g.doubleclick.net/~a/zjqZ-rCM9U70EmpWCw0hWgdDUVA/1/di" border="0" ismap="true"&gt;&lt;/img&gt;&lt;/a&gt;&lt;/p&gt;&lt;div style="width: 344px" class="image-attach-teaser"&gt;&lt;a href="/reviewer/integral-calculus/example-5-plane-areas-in-polar-coordinates"&gt;&lt;img src="http://www.mathalino.com/sites/default/files/images/013-four-leaved-rose.jpg" alt="int-015 Area of four-leaved rose by integration" title="int-015 Area of four-leaved rose by integration"  class="image image-preview " width="344" height="297" /&gt;&lt;/a&gt;&lt;/div&gt;
&lt;!-- google_ad_section_start --&gt;&lt;h3&gt;Example 5&lt;/h3&gt;
&lt;p&gt;Find the area enclosed by four-leaved rose r = a cos 2&lt;font face="Times New Roman, Times, serif"&gt;&amp;theta;&lt;/font&gt;.&lt;/p&gt;
&lt;h4&gt;&amp;nbsp;&lt;/h4&gt;
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&lt;/div&gt;&lt;img src="http://feeds.feedburner.com/~r/Mathalinocom-OnlineEngineeringMathematics/~4/EBTLLBR3bxY" height="1" width="1"/&gt;</description>
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 <pubDate>Wed, 10 Mar 2010 06:51:36 +0000</pubDate>
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